No. If a voltage is applied across a resistor, a current flows through it.
Current flows in loops, voltage drops across elements. With relation to current, what flows in, must flow out, so no, current is not dropped across a resistor, it flows through a resistor and voltage is dropped across the resistor.
A resistor affects the flow of electricity in a circuit by reducing the current that flows through it. This reduction in current leads to a decrease in voltage across the resistor.
Current flows through a resistor, not across it.
Normally through the resistor's internal construction. It flows through any part of the resistor that has low resistance- be it anywere. And then there's this. It might be that one should consider that current flows through a resistor and voltage is dropped across a resistor. Perhaps this is where the question began. The former is fairly straight forward. The latter can be vexing. Voltage is said to be dropped across a resistor when current is flowing through it. The voltage drop may be also considered as the voltage measureable across that resistor or the voltage "felt" by that resistor. It's as if that resistor was in a circuit by itself and hooked up to a battery of that equivalent voltage.
A resistor reduces the flow of current in an electrical circuit, which in turn affects the voltage across the resistor.
An ammeter is a low voltage voltmeter in parallel with a small resistance resistor. Current flow through the resistor creates a voltage drop across it which is then measured by the voltmeter.
A resistor limits current in an electrical circuit by impeding the flow of electrons, which reduces the amount of current passing through it. This, in turn, helps regulate the voltage in the circuit by creating a drop in voltage across the resistor.
None. A diode does not have a resistor in it. Diodes and resistors are different devices used for different purposes. For example, increasing current flow through a resistor increases the voltage drop across the resistor. Increasing current flow through a diode (within the diode's capabilities, just the same as a resistor) will actually decrease the voltage drop across the diode (once the diode "turns on" this voltage variance will be fairly small, though).
Current = charge (electrons) flowing through a resistor.Voltage = energy lost across a resistor.Power = energy lost across a resistor per second.So yes you are correct. Current is established through a component, while voltage and power are established across a component.Answer'Voltage' is a synonym for 'potential difference'. As the name implies, voltage describes the difference in potential between (or 'across') two different points. So voltage is applied ACROSS a resistor.Further to the original answer. voltage is NOT equivalent to 'the energy lost across a resistor', and power is NOT 'established across a resistor' (power is simply a 'rate', nothing more)!
Voltage / Resistance = Current, you do the math
It may be better to say that a resistor allows current flow through itself rather than to say that a resistor is a device that will "use" current. It does "resist" current flow, and thus limits it to some degree depending on its resistance. (More resistance means more limiting of current flow.) The resistor "drops voltage" as well limits current. A resistor "feels voltage" from some source, and the voltage it "feels" is said to be the "voltage drop" of the resistor. The voltage drop is the voltage that could be measured across that resistor with a meter.
When the voltage is increased across a metal film resistor, the current flow will also increase. Ohm's law states that the current flowing through a resistor is directly proportional to the voltage across that resistor. I = V/R Let us assume an initial voltage drop across a 4.99K ohm metal film resistor is 5V. The current flow through the resistor is calculated to be: I = 5/4990 = 0.001 Amps or 1 mA If that voltage were to say double to 10V: I = 10/4990 = 0.002 Amps or 2 mA Using these values it is also possible to calculate the power dissipated by the resistor. P = I*V = 0.002 * 10 = 0.02 Watts This power calculation determines the minimum physical case size needed for the resistor to function within these conditions. Anything smaller, the resistor will fail.