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There is insufficient information in the question to answer it. You need to provide either the voltage across the resistor, or the power dissipated by the resistor. please restate the question.

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What is the current through a 1.5k resistor with voltage of 3V across it?

Two milliamperes. Ohm's law: Current equals voltage divided by resistance.


What is the voltage drop of a 1k ohm resistor?

It depends on the current going through it. Ohm's law: Voltage equals current times resistance.


If V in battery voltage equals 5volts Resistor 1 equals 6ohms and Resistor 2 equals 4ohms What will be the volt meter Vout read?

4.5 Volts


How measure the value of resister?

To measure the value of a resistor, apply a voltage and measure the voltage across the resistor and the current through the resistor. Use Ohm's law: Resistance equals Voltage divided by Current. Start with a small voltage and increase gradually until a reading is obtained, but be careful that the power dissipation (watts = volts times amperes) of the resistor is not exceeded. Simpler solution: Use an ohmeter.


When the current traveling through a resistor is increased what happens to the voltage that travels through the same resistor?

Your question reveals fundamental misunderstandings about the nature of electricity.'Voltage' is simply another word for 'potential difference', and a potential difference appears across opposite ends of the resistor; it doesn't 'travel through' that resistor! Current, on the other hand, DOES 'travel through' the resistor and is caused by the potential difference across the resistor.Resistance is the ratio of potential difference to current. So if the resistance remians unchanged when the current through it doubles, then it has happened because the potential difference has doubled.


Current times resistance equals what?

The voltage across a resistor multiplied by the current flowing through it equals the power dissipated by the resistor, according to Ohm's Law (P = V * I). So, the relationship between current and resistance is not directly related in that way.


What is the voltage drop through a resistor of 6 ohms and 2 amps?

12 volts...! The voltage drop across a 2 ohm resistor depends on the current flowing through it. As voltage (E) equals current (I) times resistance (R), if 1/2 amp is flowing through your 2 ohm resistor, 1/2 times 2 = 1 volt. If 1 amp is flowing through your 2 ohm resistor, 1 times 2 = 2 amps. Piece of cake. If the two ohm resistor is the only component in the circuit, it will drop whatever the applied voltage is. Put a 2 ohm resistor across a 6 volt battery, it drops 6 volts. If you put your 2 ohm resistor across a 9 volt battery, it drops 9 volts. Another way to say voltage drop may help. The voltage drop across a resistor is the voltage it "feels" when in a circuit. And that last couple of examples says that very well. In a circuit where a given resistor is the only component, it drops all the voltage in the circuit. It "feels" all the voltage in the circuit. In a circuit where there are 2 resistors of equal value in series, each one drops or "feels" half of the applied voltage. (The sum of the voltage drops equals the applied voltage.) As you work more with simple circuits using resistors in different arrangements with a given voltage source, try thinking of the voltage drop of a resistor as the voltage it "feels" when the circuit is energized.


How to find the potential difference across a resistor in an electric circuit?

To find the potential difference across a resistor in an electric circuit, you can use Ohm's Law, which states that voltage (V) equals current (I) multiplied by resistance (R). So, you can calculate the potential difference by multiplying the current flowing through the resistor by the resistance value of the resistor.


How do you calculate electrical power?

Voltage x current. In a resistor for example it is the voltage drop across it that is relevant, it may be part of a circuit.


What is the power dissipated by a resistor that has 5 amps flowing through it with 120 volts applied?

The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).


If the volts going in equals 5 and there is a resistance that equals 6 what would be the volts coming out?

The question is a bit ambiguous, but I will try to address it. If the 6 ohm resistance is in series with another resistance then some of the 5 volts would be dropped across the 6 ohm resistance and the remainder of the voltage would be dropped across the other resistance. To calculate the voltage, use the 'resistor voltage divider equation' (Google it). If the 5 volts is applied across only a 6 ohm resistance, then the top of the resistor is at 5 volts and the bottom of the resistor would be at 0 volts. The resistor would drop all of the voltage.


What is the current if voltage equals 14.4 V and resistance equals 1.6 ohms?

I = V / R = (14.4 / 1.6) = 9 AmperesNote: Stand back! The resistor dissipates 129.6 watts.