The question is a bit ambiguous, but I will try to address it.
If the 6 ohm resistance is in series with another resistance then some of the 5 volts would be dropped across the 6 ohm resistance and the remainder of the voltage would be dropped across the other resistance. To calculate the voltage, use the 'resistor voltage divider equation' (Google it).
If the 5 volts is applied across only a 6 ohm resistance, then the top of the resistor is at 5 volts and the bottom of the resistor would be at 0 volts. The resistor would drop all of the voltage.
Resistance = 11 ohmsCurrent = 2 amperesVoltage = 22 volts
volts divided by resistance equals maximum amperage (current)
The formula you are looking for is R = E/I
Watts is volts times amps, so 12 x 30 = 360 watts
The current through the wire can be calculated using Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). In this case, the current would be 90 volts divided by 30 ohms, which equals 3 amperes.
Ohm's Law: Voltage = Amperes times Resistance 9 volts = amps * 10 ohms amps = .9
Amperes does not convert into volts they are two different values. Become familiar with the following formula and look at the relationships between the values. Volts = Amps x Resistance, Amps = Volts / Resistance and Resistance = Volts / Amps.
It usually represents current in amps as in the equation V=IR (volts equals current times resistance)
Volts time amps equals watts so watts divided by volts equal amps.
take your multimeter and set it to volts, going into the solenoid you should have anywhere from 12.2 to 14v and coming out it should not drop anymore than 1 volt. If it does the solenoid has to much resistance and should be replaced
If the voltage is 500 volts, and the power is 200 kilo-watts, then the current is 400 amperes. (Watts equals Volts time Amperes)The resistance of the conductor has nothing to do with this calculation, but that fact that the conductors are 0.1 ohms means that the voltage drop across each conductor is 40 volts. (Volts equals Amperes times Ohms) Since there are two conductors, the total voltage drop is 80 volts, and the voltage available to the load will be 420 volts.
These do not convert. ma (milliamps) is a unit of electric current, while volts is a unit of voltage. They are related by Ohm's Law: V = I*R, with V is voltage (volts), I is current (amps), and R is resistance (Ohms).