total resistance of a parallel connection network of resisters is equals the total resistance divided by one. 1/total R = 1/R1+1/R2+1/R3+................+1/RN since we get 1/total R from the above formula, to get total resistance (total R) just reciprocate the answer. secondly, if u have only two resistors connected in parallel say R1 & R2, then total Resistance total R=(R1*R2 )/R1+R2 inform.mayaprasad@gmail.com
If the parallel resistors are equal, then the total resistance (in this case, with three resistors) will decrease by a factor of 3. I suggest you verify this with the standard formula for parallel resistance: 1/R = 1/R1 + 1/R2 + 1/R3, replacing the value 30 for R1, R2, and R3, and calculating R, the combined resistance.
Consider t resistors with same Ohmic values. If they are in series total resistance Rt = R1 + R2. if they are in parallel then total resistance Rt = 1/R1 + 1/R2. Series connection will have higher resistance.
To solve for resistors in parallel take the inverse of the sum of the inverses of all the resistors: 1/((1/r1) + (1/r2) + (1/r3)...)[Google this. It is a lot easier to understand when the proper notation can be drawn.] SO: Rt = 1/((1/70) + (1/30)) = 21ohms
The total resistance is 5 ohms. Scroll down to related links and look at "Parallel Resistance Calculator".
The resistors should be connected in parallel .
Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.
when we want maximum resistance they are connected in series. when resistors are connected in series total resistance is maximum when resistors are connected in parallel total resistance is minimum for series total R=R1+R2+R3......... for parallel R1 in parallel to R2 total 1/R=(1/R1)+(1/R2) ie R=(R1*R2)/(R1+R2)
If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
When resistors are wired in series, their resistances are added to find the total resistance. If they are run in parallel, or series-parallel, the formula is different
That depends ... in a very interesting way ... on whether they are connected in series or in parallel. -- If the resistors are in series, then the total resistance increases when you add another resistor, and it's always greater than the biggest single one. -- If the resistors are in parallel, then the total resistance decreases when you add another resistor, and it's always less than the smallest single one.
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
The equivalent total resistance of resistors connected in parallel is lower than the resistance of the smallest resistor. The general formula for calculating the total resistance of n resistors in parallel is Rt = 1 / (1/R1 + 1/R2 + ... 1/Rn) For two resistors in parallel, the formula simplifies to Rt = (R1 x R2) / (R1 + R2) If R1 = 10K ohms and R2 = 4.2K ohms, the total resistance of R1 in parallel with R2 is (10,000 x 4,200) / (10,000 + 4,200) = 2957.7 ohms. The total resistance is less than the smallest resistor (4.2K). For three resistors in parallel, the formula is Rt = 1 / (1/R1 + 1/R2 + 1/R3) If R1 = 100 ohms, R2 = 68 ohms, R3 = 1K ohm, the total resistance of these three resistors connected in parallel is: Rt = 1 / (1/100 + 1/68 + 1/1000) = 38.9 ohms The total resistance (38.9 ohms) is lower than the smallest resistor (68 ohms).
resistance inparallel decrease in value proportionally two resistance can be calculated as R1XR2/SUM OF R1+R2. many values can be calculated as a fraction 1/r+1/r2+1/3 ....and take the total sum reciprocal
If the resistors are in series, then the total resistance is simply the sum of the resistances of each resistor.