If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.
no
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
The total resistance of a set of resistors in parallel is found by adding up the reciprocals of the resistance values, and then taking the reciprocal of the total. By removing a resistor the total current will lower. If you short out the parallel circuit as suggested it will take out the fuse that should be protecting the circuit.AnswerShorting-out a resistor in a parallel circuit, will act to short out the entire circuit, therefore, significantly increasing, not lowering, the current! And, as the previous answer indicates, this short-circuit current will operate any protective devices, such as a fuse.In a parallel circuit current does not lower but it will be increase if shorting-out one resistor in the two resistor parallel circuit, the circuit will become very low resistive and the larger current will flow through the short path.
If you are looking for the resistance of each resistor in either a series circuit or a parallel circuit you must measure the current I and the voltage V for each resistor. Then calculate its resistance using Ohms Law R = V / I where I = current (Amps), V = voltage (Volts) and R= resistance (Ohms).
No, the total resistance increases.
2
The smallest resistor.
no
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.
To calculate the total current in the circuit, you first need to find the total resistance by using the formula for resistors in parallel: 1/Total Resistance = 1/120 + 1/60 + 1/40. Once you have the total resistance, you can use Ohm's Law: Current = Voltage / Total Resistance. Finally, to find the current running through the 40 ohm resistor, you divide the total current by the resistance of the 40 ohm resistor.
It depends on the values of the individual resistors. But if each resistor is identical, then the total resistance will be one-quarter that of an individual resistor.
The total resistance would be 40 ohm.
The total impedance of a circuit with a capacitor in parallel with a resistor is calculated using the formula Z 1 / (1/R 1/Xc), where Z is the total impedance, R is the resistance of the resistor, and Xc is the reactance of the capacitor. This formula takes into account the combined effects of resistance and reactance in the circuit.
Placing another resistor in parallel to an existing resistor will lower the total resistance in the circuit. RParallel = 1 / Summationi=1toN (1 / Ri)
6
In series, you just add the resistor values together to find the total resistance. In parallel you can use the following equation you can find the total resistance by multiplying the lowest and highest resistor value, the dividing that by the sum of all the resistor values you have in parallel. you could also take the inverse of all the inverses of you resistor values added together.