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How can three resistors of 2 ohm 3 ohm and 4 ohm be connected to give a total resistance of 4 ohm?
Wiki User
∙ 11y ago
2 in series with 3&4 in parallel
Wiki User
∙ 11y ago
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What is the total resistance in a circuit that contains three 60 resistors connected in series?
The total effective resistance of resistors in series is the sum of the individual resistances.Three 60-ohm resistors in series have a total effective resistance of (60 + 60 + 60) = 180 ohms.
What is the rule for finding the total resistance of a number of resistors connected in series?
If the resistors are in series, then the total resistance is simply the sum of the resistances of each resistor.
You are just asking that let us assume you have connected 2 or 3 resistors in a circuit and the current flowing through the circuit and from all the resistors will be same but how?
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
When 2 resistors are connected in parallel r1r2 are?
Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.
What is the total resistance of a circuit that contains two 100 resistors connected in paralle?
50 ohms
How do you connect several resistances if you want to decrease in total resistance without reducing the number of resistors?
The resistors should be connected in parallel .
What is the totalresistance in a curcuit that contains three 60 ohms resistors connected in a series?
In a series circuit, just add all the individual resistances, to get the total resistance.
How do you calculate the joint resistance in a series circuit with three resistances?
The resistance of a series circuit is simply the sum of the individual resistors.
What is the total resistance in a circuit that contains three 60 ohms resistors connected in a series?
The total effective resistance of resistors in series is the sum of the individual resistances.Three 60-ohm resistors in series have a total effective resistance of (60 + 60 + 60) = 180 ohms.
A 24 volt battery supplies three devices wired in parallel that each have a resistance of 9 ohms. What is the voltage drop across each device?
A simple circuit has three resistors connected in series. The resistors are 14 ohms 12 ohms and 9 ohms. What is the total resistance of the circuit?
How are resistor connected in series?
when we want maximum resistance they are connected in series. when resistors are connected in series total resistance is maximum when resistors are connected in parallel total resistance is minimum for series total R=R1+R2+R3......... for parallel R1 in parallel to R2 total 1/R=(1/R1)+(1/R2) ie R=(R1*R2)/(R1+R2)
What is the relation between the total resistance of a parallel connection network of resistors in reference to their single resistance?
The equivalent total resistance of resistors connected in parallel is lower than the resistance of the smallest resistor. The general formula for calculating the total resistance of n resistors in parallel is Rt = 1 / (1/R1 + 1/R2 + ... 1/Rn) For two resistors in parallel, the formula simplifies to Rt = (R1 x R2) / (R1 + R2) If R1 = 10K ohms and R2 = 4.2K ohms, the total resistance of R1 in parallel with R2 is (10,000 x 4,200) / (10,000 + 4,200) = 2957.7 ohms. The total resistance is less than the smallest resistor (4.2K). For three resistors in parallel, the formula is Rt = 1 / (1/R1 + 1/R2 + 1/R3) If R1 = 100 ohms, R2 = 68 ohms, R3 = 1K ohm, the total resistance of these three resistors connected in parallel is: Rt = 1 / (1/100 + 1/68 + 1/1000) = 38.9 ohms The total resistance (38.9 ohms) is lower than the smallest resistor (68 ohms).
