I'm going to take this as "How do you connect resistors is series?" just connect one wire of the first resistor to one wire of the second.
connect 2 2ohm resistors in parallel and connect it to a series 2ohm resistor
Reduce current - reduce power.
When many resistances are connected in series, the equivalent resistance is greater than the greatest single resistance. When many resistances are connected in parallel, the equivalent resistance is less than the smallest single resistance.
You can connect 4 resistors in series-parallel, i.e. two in series, both in parallel with another two, and the effective resistance would be the same as one resistor. Similarly, you can connect nine resistors in 3x3 series-parallel, or 16 resistors in 4x4 series-parallel, etc. to get the same resistance of one resistor.
It depends on the resistance of each resistor. If each resistor, for example, is 0.333 ohm, then you could connect them in series. If each resistor, for example, is 3 ohms, then you could connect them in parallel.
ammeter connect in series in circuit to measure the current, if the Ammeter have a high resistance it would effect the voltage value because there will be a drop voltage over the internal resistance of the Ammeter, so we desgin the ammeters with very low resistance...
If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.
The resistance of a series circuit is simply the sum of the individual resistors.
Connect a large but precisely known resistance in series with the galvanometer. For example, if you connect a 1-Megohm resistor in series with it, then the galvanometer will indicate 1 microampere of current when it's connected across a potential difference of 1 volt ... quite a sensitve voltmeter.
Connect 50 of them in series. This would have 50 ohm as equivalent. Same way have another 50 pieces in series. This again would have 50 ohm as effective value. Now connect these in parallel to each other. Now the effective would become as 25 ohm.
If you add a second resistor, the resistance of series circuit will increase.
Assuming galvanometer has zero or negligible internal resistance. If u connect resistor R>>RL(Load resistance) and connect it parallel to RL, it will hardly cause any change in voltage across load resistance. Suppose small current Ig goes through galvanometer. Since galvanometer have zero internal resistance, Voltage across RL = Voltage across R = IgR