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How do you draw this you have three 20 ohm resistors available. how would you connect these three resistors to produce a 30 ohm equivalent you must use all three resistors?
You can achieve a 30 ohm equivalent resistance by connecting the resistors in a combination of series and parallel. Connect two resistors in series to get 40 ohms, then connect the third resistor in parallel with this combination to achieve a total resistance of 30 ohms.
Three 8.0-W resistors are connected in series What is their equivalent resistance?
The equivalent resistance of resistors connected in series is simply the sum of their individual resistances. Therefore, the equivalent resistance of three 8.0-W resistors connected in series is 24.0 W.
Is resistor measured in amps?
No, resistors are measured in ohms, not amps. Ohms represent the resistance offered by the resistor to the flow of current, whereas amps (amperes) represent the measure of current flowing through a circuit.
How will you join 3 resistors of 2 ohm each so that the effective resistance is 3 ohm?
You can achieve an effective resistance of 3 ohms by connecting the resistors in series. Connect two resistors in series to get a combination of 4 ohms. Then, connect this combination in parallel with the third resistor to achieve an overall resistance of 3 ohms.
How do you create a circuit which has a 13.75 Ohm resistance using only 1Ohm resistor?
If you're sure that every resistor is exactly 10 ohms, and you need exactly13.75 ohms, then you can do it this way:-- Connect four resistors in parallel. Effective resistance of the combination = 2.5 ohms.-- Connect eight resistors in parallel. Effective resistance of the combination = 1.25 ohms.-- Connect in series: the 4-resistor unit, the 8-resistor unit, and a single 10-ohm resistor.Effective resistance of the combination = (2.5 + 1.25 + 10) = 13.75 ohms.In the real world, however, the combination of (2.5 + 10) = 12.5 would be closeenough to work. And actually, a single 10-ohm resistor might be close enough.Or you could just connect a single 10-ohm resistor to the ohm-meter, take afingernail file, file a small notch in the side of the resistor while watching themeter, stop filing when the resistance arrives at 13.4 ohms, see what it is whenit cools from all the filing and settles down, then make small additional scrapesuntil you have your 13.75 ohms. This might be just as fast as the 23 solder-joints required for the procedure described above, and you save 12 resistors !So what could be bad ! ?
A resistor of 10k ohms resistance with tolerance of 5 percent is connected in parallel with another resistor of 5k ohms resistance and 10 percent tolerance.what is tolerance limit of parallel network?
6.67%
How do you place 3 resistance to get the total resistance of 1 ohm?
It depends on the resistance of each resistor. If each resistor, for example, is 0.333 ohm, then you could connect them in series. If each resistor, for example, is 3 ohms, then you could connect them in parallel.
What resistance must be connected in parallel to 6.0-ohm resistor to reduce the combined resistance to 15-ohm?
No such resistor exists. Any resistor placed in parallel with a 6.0 ohm resistor is going to reduce the combined resistance below 6.0 ohms.
When 2 resistors are connected in parallel r1r2 are?
Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.
What is the equivalent resistance of three resistor with 3 ohms connected in star?
There is no 'equivalent resistance' for three resistors connected in star.
What is the relation between the total resistance of a parallel connection network of resistors in reference to their single resistance?
The equivalent total resistance of resistors connected in parallel is lower than the resistance of the smallest resistor. The general formula for calculating the total resistance of n resistors in parallel is Rt = 1 / (1/R1 + 1/R2 + ... 1/Rn) For two resistors in parallel, the formula simplifies to Rt = (R1 x R2) / (R1 + R2) If R1 = 10K ohms and R2 = 4.2K ohms, the total resistance of R1 in parallel with R2 is (10,000 x 4,200) / (10,000 + 4,200) = 2957.7 ohms. The total resistance is less than the smallest resistor (4.2K). For three resistors in parallel, the formula is Rt = 1 / (1/R1 + 1/R2 + 1/R3) If R1 = 100 ohms, R2 = 68 ohms, R3 = 1K ohm, the total resistance of these three resistors connected in parallel is: Rt = 1 / (1/100 + 1/68 + 1/1000) = 38.9 ohms The total resistance (38.9 ohms) is lower than the smallest resistor (68 ohms).
Two identical resistors are connected in parallel and then wired in series to a 40-ohm's resistor If the total equivalent resistance is 55-ohm's. What is the value of R?
30 ohms.
Why are resistances parallel to short circuits neglected in a circuit?
You can consider a short circuit to be a resistor with R=0 Ohms. It is then clear by the equation for calculation of parallel resistance that the combined resistance of a resistor in parallel to a short circuit is 0. Consider the following example with R1= 1k Ohms and R2= 0 Ohms: Rtotal = R1*R2 / (R1+R2) = R1*0 / R1 = 0 Ohms.
What is the total resistance of a circuit with a 75 ohm and a 150 ohm resistister in parallel?
The equivalent resistance of 75 ohms and 150 ohms in parallel is(75 x 150)/(75 + 150) = 50 ohms
What is the total resistance of a 6-ohm resistor and a 12-ohm resistor in a parallel series?
In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms
How do you draw this you have three 20 ohm resistors available. how would you connect these three resistors to produce a 30 ohm equivalent you must use all three resistors?
You can achieve a 30 ohm equivalent resistance by connecting the resistors in a combination of series and parallel. Connect two resistors in series to get 40 ohms, then connect the third resistor in parallel with this combination to achieve a total resistance of 30 ohms.
Given 4 resistors each have equivalent resistance of 100 ohms show how these resistors might be combined to produce an equivalent resistance of a 40 ohms b 250 ohms c 100 ohms?
a) Put 2 of the resistors in series to make a 200 ohm resistor. Then put the 100, 100, and 200 ohm resistors in parallel for 40 ohms. b) Put 2 resistors in parallel for 50 ohms. Put the 50, 100, and 100 ohm resistors in series for 250 ohms. c) Put 2 resistors in parallel for 50 ohms. Repeat with other 2 resistors. Put the two 50 ohm resistors in series for 100 ohms. This configuration can withstand 4 times the wattage of each individual resistor.
