That depends on you. If you want, you can say 1 watt should be 0 dB.
5 watts +/- 3 dB
Given: Power P = 100 W. Reference power Po = 10^−3 W = 1 mW. Reference power level LPo = 0 dB. Get power P when entering power level LP: P = Po×10^(LI/10) W = 10^−3×10^(LP/10) W. Get power level LI in dB when entering power P in W. LP = 10×log (P / Po) dB = 10×log (P / 10^−3) = 50 dB. The reference power may be different, then the power level will be different.
A decibel is a measure of relative power, to compare one power level with another. 'dBm' means dB relative to 1 milliwatt and is a common unit of power in communications systms, and 0 dBm is the same thing as 1 milliwatt.
Impossible question, like asking "One Apple is equal to how many oranges" Simply set : Decibels it the unit of volume, how loud things go hertz is how fast things change, the frequency (number of changes per second). When you talk about music, different frequencies can have a different volume. You can even measure the volume in frequency ranges - look up : paragraphic equalizer for the principle. Geert Fieuw Beyond The Labyrinth ----------------------------------------------------------------------- +db= 10*log(p2/p1) +db= 10*log(2watts/1watt) +db= 10*log(2) +db= 10*.30103 +3.0103= 10*log(2watts/1watt) so double the power you gain 3db's so double the sound you gain 30dbs and p2 is 1000 times p1 +db= 10*log(p2/p1) +db= 10*log(1000watts/1watt) +db= 10*log(1000) +30= 10*3 test signal say 60 Hz
That depends on you. If you want, you can say 1 watt should be 0 dB.
5 watts +/- 3 dB
Decibels (db) is relative power, log base 2, times 3. Increasing power from 200 watts to 400 watts is doubling power, so the decibel change is +3 db.800 watts would be +6 db, 1600 watts would be +9 db, 100 watts would be -3 db, 50 watts would be -6 db, and so on.
It depends on the reference. If the reference electric power is P0 = 1 W (0 dB) then 98 dB equals 6309573444.8 Watts.
In power wattage increases by two times for every three DBs of increase. A starting point is needed to do this calculation. The equation you're looking for is 10*log |P| = P in dB for example, 0 dB = 1 watt 10 dB = 10 watts for 13.936dB, 10^1.3936 = 24.75 watts.
40 watts
IL is not equal to SPL. Actually SPL = IL + 0.16dB.
Given P = 100 watts. Reference sound intensity Po = 10^−12 W. Reference sound intensity level LPo = 0 dB. Get power level LP in dB when entering sound power P in watts. Power level LP = 10×log (P / Po) dB = 10×log (100 / 10^−12) = 140 decibels (dB).
If you want to work in watts, convert 25dB to a scalling factor: 3dB = 2 x input 10dB = 10 x input 20dB = 100 x input ...25dB = 10 ^ (25/10) = 316.2 x input So the output is 15 micro Watts x 316.2 = (4700)/(10^6) = 4.7 milli watts If you want to work in dB, then convert 15 micro watts to dB: 10 * log |P| = dB = 10*log |15 x 10^6| = -48.2dB ***When you have very small (ie negative) dB, it is often referred to in dBm, or 1/1000 of dB ( 30 dBm = 0 dB) so the output is -18.2dBm + 25 = 6.8dBm, or -23.2dB
60 dB sound pressure level is about conversational speech listened in 1 meter distance.
90 decibel is 32 sones.
One decibel (dB) is equal to one tenth of a bel (B).