The switch will use no wattage whatsoever. The load on that switch is what uses power. If you know the load is 5 amps then 5 amps at 120 volts is 600 watts.
A typical iPod uses 12 v at 1 amp, and with the adaptor for 110/220 v the total consumption is about 20 W.
There are no "watts" in 2.5 volts. Wattage is the result when you multiply volts times amps. You cannot answer the question with only one quantity (in this case 2.5 volts). If you have 1 amp and 2.5 volts, they you would have 2.5 watts. If you had 2 amps and 2.5 volts, they you would have 5 watts. The formula is Volts X Amps = Watts.
A transformer does not use, it transforms voltage from one value to another. The output amperage is governed by the connected load. If the load wattage is higher than the wattage rating of the transformer then either the primary or secondary fuse will blow or the transformer will burn up if the fusing is of the wrong sizing. The maximum primary amperage can be found by using the following equation, Amps = Watts/Volts, A = W/E = 600/120 = 5 amps. The same equation is used for the calculating the maximum secondary amperage, A = W/E = 600/12 = 50 amps.
The formula you are looking for is I = W/E, Amps = Watts/Volts. Amps = 5000/230 =21.7 amps. The wire size to run this heater would be a #10 copper conductor. The supply breaker would be a two pole 30 amp breaker.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
The switch will use no wattage whatsoever. The load on that switch is what uses power. If you know the load is 5 amps then 5 amps at 120 volts is 600 watts.
Ohms law will tell you watts equals volts times amps: 115 x 5 = 575
It looks like the crucial number was left out of the question, between the words "volt ... amp DC". If the device says it needs 5 volts at 2 amp, it will run safely on any DC power supply rated at 5 volts and (2 or more) amps.
A typical iPod uses 12 v at 1 amp, and with the adaptor for 110/220 v the total consumption is about 20 W.
No you can not. The power supply output of 1.2 amps is under sized. You would need to have a power supply of 3 amps or larger.
There are no "watts" in 2.5 volts. Wattage is the result when you multiply volts times amps. You cannot answer the question with only one quantity (in this case 2.5 volts). If you have 1 amp and 2.5 volts, they you would have 2.5 watts. If you had 2 amps and 2.5 volts, they you would have 5 watts. The formula is Volts X Amps = Watts.
The 5 amp fuse has many wattages that it can protect. It depends on the voltage of the circuit that the fuse is protecting. Use the following formula, Watts = Volts x Amps. For example 120 volts x 5 amps = 600 watts, 240 volts x 5 amps = 1200 watts, 480 volts x 5 amps = 2400 watts and 600 volts x 5 amps = 3000 watts.
you would need to know the wattage of each lamp. multiply the lamp wattage x 5 = total watts divide the total wattage / 230 volts (or the voltage you will connect to)= amps example: 250 watts x 5= 1250 watts 1250 watts / 230 volts = 5.43 amps
A transformer does not use, it transforms voltage from one value to another. The output amperage is governed by the connected load. If the load wattage is higher than the wattage rating of the transformer then either the primary or secondary fuse will blow or the transformer will burn up if the fusing is of the wrong sizing. The maximum primary amperage can be found by using the following equation, Amps = Watts/Volts, A = W/E = 600/120 = 5 amps. The same equation is used for the calculating the maximum secondary amperage, A = W/E = 600/12 = 50 amps.