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To answer this question, let's think about the excitation and relaxation processes involved. In the excitation process inside a deuterium lamp, an electrical arc between an oxide coated filament and an electrode excites D2 to D2*. Next, the D2* dissociates into individual D atoms. Let's call these D' and D''. Also, a photon of light is released. For an individual event, the total energy posssessed by D2* is apportioned between the kinetic energies of D', D'', and the photon. The sum of the kinetic energies of D' and D'' can vary from almost zero to the original energy of D2*. If the kinetic energies of D' and D'' are relatively small, the energy of the photon is large, and a shorter wavelength of light is emitted. If the kinetic energies of D' and D'' are relatively large, the energy of the photon is small, and a longer wavelenght of light is emitted. In a population of D2*, a distribution of kinetic energies of D' and D'' will result, allowing for a continuum spectrum to be emitted from the lamp.

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A deuterium lamp produces a continuous spectrum because the deuterium gas inside the lamp emits a broad range of ultraviolet (UV) light as electrons move between energy levels in the gas. This results in a continuous distribution of wavelengths, rather than distinct emission lines like in a gas discharge lamp.

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Q: 7 Why does a deuterium lamp produce a continuous rather than a line spectrum in the UV?
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