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The 8086 can address 1,114,080 bytes. (One Mb + 64Kb - 16) That does not count I/O space, it only counts memory space.
mov
There are 256 different interrupt vectors in the 8086/8088. Each vector is a far CS:IP address, which is four bytes. That makes the interrupt vector table 1,024 bytes.
There are 74 instructions in the 8085 microprocessor.
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
jmp
In 8086 the instruction queue is 6 byte long. This is because even the longest 8086 instruction is 6 byte long. Thus it is possible to prefetch even the longest instruction in the instruction set.
The 8086 was only capable of addressing 1Mbyte of memory. It was divided into segments of 65536 bytes (64 KB) each meaning about 16 segments.
The Intel 8086/8088 is not a 32 bit machine. It is a 16 bit machine. It has 72 instruction types.