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Intel 8086 and 8088

The Intel 8086/8088 family of microprocessors is a 16 bit architecture on a 16 bit (8086) or an 8 bit (8088) bus. The 8088 was the processor in the original IBM PC, and has evolved into the most popular processor used today in PC's and servers.

1,056 Questions

How many wires are there on an address bus for modern cpu's?

The number of wires on an address bus for modern CPUs typically ranges from 32 to 64 bits, meaning there are usually 32 to 64 individual wires. This allows them to address anywhere from 4 GB (in a 32-bit system) to 16 EB (in a 64-bit system) of memory. Some specialized or high-performance processors may use wider address buses, but 32 and 64 bits are the most common in contemporary consumer CPUs.

What is hardware interrupt of 8085 microprocessor with vector interrupt?

In the 8085 microprocessor, a hardware interrupt is a signal from an external device that temporarily halts the CPU's current operations to allow the device to communicate with the processor. A vector interrupt specifically refers to an interrupt that has a predefined memory address (vector) associated with it, which the processor jumps to when servicing the interrupt. For instance, the 8085 has several hardware interrupts, such as INTR, RST 7.5, RST 6.5, and RST 5.5, each with its own unique vector address, allowing for efficient and organized handling of multiple interrupt sources. This mechanism enables real-time processing and responsiveness to external events in embedded systems.

What is the Difference of Address line 1 and Address line 2?

Address Line 1 typically includes the primary address information, such as the street number and name, for example, "123 Main St." Address Line 2 is used for additional address details that may be necessary, such as apartment numbers, suite numbers, or building names, like "Apt 4B" or "Building C." This format helps ensure that the full address is complete and accurate for delivery or location purposes.

Where 8086 microprocessors are used.......And even i want to know the applications of 8086..?

The 8086 microprocessor is primarily used in embedded systems, industrial automation, and control systems due to its simplicity and efficiency. It serves as a foundational component in early personal computers and is still utilized in educational settings for teaching computer architecture and assembly language programming. Additionally, it finds applications in legacy systems and hardware that require basic processing capabilities. Its architecture also paved the way for more advanced processors, influencing modern computing designs.

What is the maximum length of instruction in 8086?

In the 8086 microprocessor, the maximum length of an instruction is 6 bytes. This includes the opcode, any necessary prefixes, and operands. The architecture allows for complex addressing modes, which can contribute to the instruction length, but the limit remains at 6 bytes for any single instruction.

As a memory segment is 64k does it mean that 64k are the total addresses in a segment if 64K is the total addresses in a segment then what is the sizebytes of one segment 64k?

Yes, if a memory segment is 64K, it means there are 64K total addresses in that segment. Since 1K (kilobyte) equals 1024 bytes, a 64K segment would have a total size of 64 * 1024 bytes, which equals 65,536 bytes. Therefore, the size of one segment is 65,536 bytes.

What is the effective address generated by the following combinations if they are valid. If not give reason. Initially BX0x0100 SI0x0010 DI0x0001 BP0x0200 and SP0xFFFF a. bx-si b. bx-bp c. bx plus 10?

To calculate the effective addresses for the given combinations:

a. BX - SI: This results in 0x0100 - 0x0010 = 0x00F0, which is valid. b. BX - BP: This gives 0x0100 - 0x0200 = 0xFF00, which is also valid. c. BX + 10: This equals 0x0100 + 0x000A = 0x010A, which is valid.

All combinations are valid and yield effective addresses.

What are the Advantage of using general purpose registers in 8086?

The advantages of using general-purpose registers in the 8086 microprocessor include increased flexibility for data manipulation, as they can be used for various operations such as arithmetic, logic, and data transfer. They help simplify instruction encoding by allowing the use of a uniform set of operations across different registers. Additionally, general-purpose registers facilitate efficient programming by enabling quick access to frequently used data, thereby improving overall execution speed. Lastly, the use of these registers can reduce memory access, which enhances performance by minimizing delays associated with fetching data from RAM.

What is inter segment and intra segment jump in 8086?

In the 8086 microprocessor, an intra-segment jump refers to a jump instruction that occurs within the same segment of memory, allowing the program to branch to a different address within that segment. Conversely, an inter-segment jump involves jumping to a different segment, which requires specifying both the segment and offset addresses to access the target location. Intra-segment jumps are typically faster since they do not require segment register changes, while inter-segment jumps can introduce additional overhead due to the need for segment management.

How can you calculate the physical memory of the next instruction executed by the microprocessor?

To calculate the physical memory address of the next instruction executed by a microprocessor, you typically use the program counter (PC), which holds the address of the next instruction to be fetched. The PC is incremented after each fetch, usually by the size of the instruction that was executed. In systems with paging or segmentation, you may also need to consider the current values of the segment registers or page tables to translate virtual addresses to physical addresses correctly. Thus, the physical address can be derived from the PC value, along with any necessary address translation mechanisms.

Write a code segment to find the square of a byte available in register AL using XLAT instruction microprocessor?

The XLAT instruction is used to translate a byte in the AL register using a lookup table pointed to by the BX register (or SI in some modes). However, XLAT itself does not perform arithmetic operations like squaring. To find the square of a byte in AL, you can simply multiply it by itself using the MUL instruction. Here’s a code segment for that:

    mov bl, al   ; Store original value in BL
    mul bl       ; AL = AL * BL (square of AL)

This code multiplies the value in AL by itself, storing the result back in AL.

Is the 8086 and 8088 TTL compatible?

Yes, the 8086 and 8088 microprocessors are TTL (Transistor-Transistor Logic) compatible. Both processors were designed to work with standard TTL logic levels, allowing them to interface with other TTL-compatible components in a system. However, the main difference between the two lies in their data bus width; the 8086 has a 16-bit data bus, while the 8088 has an 8-bit data bus, which affects their performance and system design.

ALE in detail 8086 microproccesor?

The ALE (Address Latch Enable) signal in the 8086 microprocessor is used to demarcate the time when the address bus is valid. It indicates that the multiplexed address/data bus (AD0-AD15) is carrying a valid address during the first part of a bus cycle. When ALE is asserted, external latches can capture and hold the address, allowing the data bus to later carry data without confusion. This functionality is crucial for enabling the proper interfacing of the 8086 with memory and peripheral devices.

Why address bus is 20 bit?

A 20-bit address bus can address 2^20 distinct memory locations, which equals 1,048,576 (or 1 megabyte) of memory. This allows the system to access a sufficient amount of RAM and memory-mapped I/O devices. The choice of a 20-bit address bus is often a design decision to balance performance and cost, enabling support for a wide range of applications without requiring larger, more expensive memory configurations.

Which flags are tested by various conditional loop instruction?

Conditional loop instructions typically test the Zero Flag (ZF) and the Carry Flag (CF) to determine the outcome of comparisons or arithmetic operations. The Zero Flag indicates whether the result of an operation is zero, while the Carry Flag is used for unsigned comparisons to indicate if a value has exceeded its range. Additionally, the Sign Flag (SF) and Overflow Flag (OF) may also be tested depending on the specific type of comparison being performed. These flags help decide whether to continue iterating or to exit the loop.

Why 8086 is important?

The 8086 microprocessor, introduced by Intel in 1978, is significant because it laid the foundation for the x86 architecture, which continues to dominate the personal computing market. Its 16-bit architecture and segmented memory model enabled more complex computing tasks and better performance compared to its predecessors. The 8086 also inspired a wide range of compatible processors and systems, making it a cornerstone in the evolution of modern computing. Its legacy is seen in contemporary CPUs and software, ensuring its importance in computer history.

What is physical address for IRS-Cincinnati Ohio 45999?

The physical address for the IRS in Cincinnati, Ohio 45999 is:

Internal Revenue Service
P.O. Box 9001
Cincinnati, OH 45999

This is a mailing address for various tax-related correspondence. For specific inquiries or services, it’s advisable to check the IRS website or contact them directly for the appropriate physical location.

8086 assembly language that accepts two input digits?

In 8086 assembly language, you can accept two input digits by using interrupts to read from the keyboard. You would typically use the INT 21h service with function 01h to read a character, storing each digit in a register or memory location. After reading both digits, you can convert them from ASCII to their numeric values by subtracting 30h from each character. This allows you to perform arithmetic operations on the input digits as needed.

How can physical address be calculated using protected mode?

In protected mode, physical addresses are calculated using a combination of segment selectors and offsets. A segment selector points to a descriptor in the Global Descriptor Table (GDT) or Local Descriptor Table (LDT), which contains the base address of the segment along with its limit and access rights. To compute the physical address, the base address from the descriptor is added to the offset provided by the program, resulting in the final physical address used by the CPU. This segmentation allows for better memory management and protection in multitasking environments.

Where can you find a 8086 MP on Multisim?

In Multisim, you can find the 8086 microprocessor by navigating to the components toolbar. Look for the "Microprocessors" category or use the search function to type "8086." Once located, you can drag and drop it into your circuit design workspace for simulation and testing. If it's not available in your version, you may need to check for additional libraries or updates.

Consider a 256x8 RAM chip a- How many 256x8 Ram chip are needed to provide a memory capacity of 4096 bytes b- How many bits will each memory address contain and address line must go to each chip?

a) To provide a memory capacity of 4096 bytes using 256x8 RAM chips, you need 4096 bytes / 256 bytes per chip = 16 chips.

b) Each memory address for the 256 locations in a chip will require 8 bits (since 2^8 = 256). Therefore, each chip will require 8 address lines to select one of the 256 locations.

What is an addressing machine?

An addressing machine is a type of computational device or system that uses specific addressing schemes to access and manage data within a memory structure. These machines utilize various addressing modes to locate and retrieve information efficiently, allowing for effective data manipulation and processing. Addressing machines are foundational in computer architecture, enabling the execution of programs and operations by directing how and where data is stored and accessed.

Why are the page size the number of pages 4 in the virtual address space and the number of page frames in the physical address space all a power of 2 Explain?

Page sizes, the number of pages in virtual address space, and the number of page frames in physical address space are typically powers of 2 because this alignment simplifies memory management and addressing. Using powers of 2 allows for efficient bit manipulation, which facilitates faster calculations for memory addressing, such as shifting bits for page offsets. Additionally, it aligns well with binary systems used in computers, making it easier to design hardware and software that can handle memory efficiently. This uniformity also aids in ensuring optimal use of memory resources and reduces fragmentation.

Which is faster- Reading word size data whose starting address is at even or at odd address of memory in 8086?

In the 8086 microprocessor, reading word-sized data is generally faster from an even address than from an odd address. This is because the 8086 architecture is designed to access memory in 16-bit (word) chunks, and even addresses allow the processor to retrieve data more efficiently, aligning with its access patterns. When a word is at an odd address, the processor must perform an additional cycle to fetch the data, resulting in slower access times.

What is the flag register?

The flag register, often referred to as the status register, is a special register in a computer's CPU that contains individual bits representing the status of various operations and conditions within the processor. Each bit, known as a flag, indicates outcomes such as zero results, carry out, overflow, and sign of the result from arithmetic and logical operations. This information is crucial for decision-making in control flow, allowing the CPU to determine subsequent actions based on previous computations. The flag register plays a vital role in facilitating conditional branching and interrupts in programming.