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Write a code segment to find the square of a byte available in register AL using XLAT instruction microprocessor?
The XLAT instruction is used to translate a byte in the AL register using a lookup table pointed to by the BX register (or SI in some modes). However, XLAT itself does not perform arithmetic operations like squaring. To find the square of a byte in AL, you can simply multiply it by itself using the MUL instruction. Here’s a code segment for that:
mov bl, al ; Store original value in BL
mul bl ; AL = AL * BL (square of AL)
This code multiplies the value in AL by itself, storing the result back in AL.
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How are the code segment address generated in 8086 microprocessor?
In the 8086 microprocessor, code segment addresses are generated using a segment:offset addressing scheme. The code segment (CS) register holds the starting address of the code segment, while the instruction pointer (IP) register holds the offset of the next instruction to be executed within that segment. The effective address of an instruction is calculated by adding the value in the CS register (shifted left by 4 bits) to the value in the IP register, allowing for a total addressable space of 1 MB. This segmentation allows for efficient memory management and organization of code.
Which register contains address of next instruction fetch in 8086 mp?
In the 8086 microprocessor, the Instruction Pointer (IP) register contains the address of the next instruction to be fetched and executed. It works in conjunction with the Segment Registers (such as CS - Code Segment) to form the complete address of the instruction in memory. The IP is automatically updated as instructions are executed, ensuring that the CPU always knows where to fetch the next instruction from.
What registers is used to keep track of address of the memory location where the next instruction is located?
Instruction pointer (IP) is used to hold the offset of the next instruction to be fetched for BIU available from Code Segment whose base address is held in CS segment base register..
What is default segment register for IP?
The default segment register for the Instruction Pointer (IP) in x86 architecture is the Code Segment (CS) register. This register is used to define the segment of memory that contains the currently executing code. When a program is executed, the CPU uses the CS register in conjunction with the IP register to determine the address of the next instruction to execute.
Why does not Motorola's microprocessor has segment register?
There is insufficient information in the question to properly answer it. Which Motorola microprocessor are you talking about? Please restate the question.
Which register can be changed directly using pop instruction in 8086?
stack segment register
Which register stores intrrupt and subroutine return address register in 8086?
In the 8086 microprocessor, the register that stores the interrupt and subroutine return address is the Instruction Pointer (IP) register. When an interrupt occurs or a subroutine is called, the current instruction address is pushed onto the stack, allowing the processor to return to that location after the interrupt or subroutine execution is complete. The IP register works in conjunction with the Code Segment (CS) register to determine the effective address of the next instruction to execute.
How many segment can be directly addressed at a particular time by 8086 microprocessor?
There are four segment registers in the 8086/8088, Code Segment (CS), Stack Segment (SS), Data Segment (DS), and Extra Segment (ES). As a result, there are four segments that can be directly addressed at a particular time, i.e. without an extra instruction to reload a segment register.
Difference between code segment and data segment of an instruction?
In the 8086/8088 microprocessor, the code segment is used to fetch the opcode and any additional instruction bytes that might be part of the instruction, while the data segment is used to fetch and/or store any operand bytes that the instruction requires to be manipulated.This is in the case of no segment override prefix.
A Explain the use of Code Segment CS and data segment DS register in 8086 microprocessor?
Code segment (CS) is a 16-bit register containing address of 64 KB segment with processor instructions. The processor uses CS segment for all accesses to instructions referenced by instruction pointer (IP) register. CS register cannot be changed directly. The CS register is automatically updated during far jump, far call and far return instructions. Data segment (DS) is a 16-bit register containing address of 64KB segment with program data. By default, the processor assumes that all data referenced by general registers (AX, BX, CX, DX) and index register (SI, DI) is located in the data segment. DS register can be changed directly using POP and LDS instructions. Code segment (CS) is a 16-bit register containing address of 64 KB segment with processor instructions. The processor uses CS segment for all accesses to instructions referenced by instruction pointer (IP) register. CS register cannot be changed directly. The CS register is automatically updated during far jump, far call and far return instructions. Data segment (DS) is a 16-bit register containing address of 64KB segment with program data. By default, the processor assumes that all data referenced by general registers (AX, BX, CX, DX) and index register (SI, DI) is located in the data segment. DS register can be changed directly using POP and LDS instructions.
What is the microprocessor of code segment register?
The code segment register (CS) is a key component in the architecture of x86 microprocessors, such as those developed by Intel. It holds the starting address of the segment that contains executable code, allowing the CPU to access instructions efficiently. The CS register works in conjunction with instruction pointers to enable the execution of programs by defining the memory segment from which the processor fetches instructions. This segmentation helps manage memory, providing a level of organization and protection for code execution.
How you calculate the physical address in 8086 microprocessor with example?
The physical address in the 8086/8088 is calculated by adding the effective address with the contents of one of the segment registers left shifted by 4 bit positions. This results in a 20 bit address bus. As an example, if the CS register contains 1234H, and the IP register contains 5678H, then the next instruction is fetched from physical address 179B8H, which is 1234H times 16 (12340H) plus 5678H. The segment register used is selected by context, or by using a segment override prefix, however, the code segment register (CS) can not be overidden during instruction fetch, nor can the stack segment register (SS) be overidden during stack pushes and pops.
