Physical address in the 8086/8088 is {Selected Segment Register} * 16 + {Effective Offset Address}. It is a 20-bit address
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It is mightily referring to Microprocessor 8086 . I think you saw "8086 microprocessor". The 8086 is nothing it indicates the number of microprocessor same as Digital or analog ic's . 8086 microprocessor has 20 Address buses and 8 data buses which has 1 Mb inbuilt memory for performing several type of airthmatical and logical operation.
segment is for converting physical address to logical address , here on taking 8086 microprocessor as example, we have 20 address lines but it is capable of taking only 16 address lines.... so to convert that 20 into 16 segment is used....
for demultiplexing address/data bus
Its 16bit microprocessor,and-> the 8086 has a 16bit databus 20bit address bus-> the intel 8086,is designed to operate in two modes namely(1) minimum mode(2) maximum mode
The 8086 microprocessor has 40 pins.
The 8086 Microprocessor operate to require frequency that is provided by clock generator to 8086 Microprocessor and also Synchronization various component of 8086.
The Instruction Pointer (IP) in an 8086 microprocessor contains the address of the next instruction to be executed. The processor uses IP to request memory data from the Bus Interface Unit, and then increments it by the size of the instruction.
queue of 8086 microprocessor is 6 bits
In the 8086 microprocessor, the physical address is calculated by shifting the segment address 4 bits to the left, which effectively multiplies it by 16. This operation aligns the segment address to the correct boundary in memory, allowing for a proper offset calculation. The combined segment and offset addresses then yield a 20-bit physical address, which can access a larger memory range than the 16-bit addresses used for segments and offsets individually. This addressing scheme enables the 8086 to utilize up to 1 MB of memory.
The 8086/8088 microprocessor has a 20 bit address bus, so the number of memory locations it can address is 220 or 1,048,576.
Pins 1 and 20 in the 8086 microprocessor are (both) power and signal ground (GND).
it is a 16 bit microprocessor & it has 40 pin .