The 8086 microprocessor has 40 pins.
Pins 1 and 20 in the 8086 microprocessor are (both) power and signal ground (GND).
Two ground pins are used in the 8086 microprocessor to increase the bus pull-down current capacity.
There are 256 ports available in the 8085 microprocessor. The IN and OUT instructions have an 8-bit port number, and that is where the 256 comes from.In order to use ports, the hardware addressing system must decode IO/M-. Some implementations don't do this, so they map IO addresses to memory addresses. In that case, you could say there are 65536 possible IO addresses, but that is not the same as ports, because ports are specific to the IN and OUT instructions.The other "problem" with IN and OUT is that you cannot specify the address in a register, while you can do so with indirect memory addressing.
WHAT IS THE PINS CONFIGURATION OF 8086?
There are ground pins on a microprocessor chip for the same reason there are ground pins on any kind of chip - to provide a current sink path for gates that need to pull to ground. If you are asking why there are two ground pins on some processors such as the 8086/8088, the answer is that one ground pin is not enough - that if all gates pulled to ground at the same time, the current transient would destabilize the processor - so two were provided.
No. The pins are preset by Intel.
40 PINS
The 8086 family of microprocessors, including the 8086, 80C86, and 80C86AL, are presented in 40-pin DIP packages.
The 8086 comes in a 40 pin package with 2 ground pins and one power pin; the remaining 37 signal pins every single one is important.
it have 40 pins 1st one is ground and last one is Vcc. Itplh = 450
The plug in pins on most processors are made of gold plated aluminum.
the pin configuration of a processor means that the diagramatic representation of block diagram of processor representing various pins and the function of that pins