No. The pins are preset by Intel.
8085 is a microprocessor designed by Intel
microprocessor 8085 is basic 8 bit microprocessor by Intel Corp. it has 64Kb memory and 16 address buses and 8 data buses it has 40 pin ic. 8 address and 8 data buses are multiplexed with each other for reducing the total number of pins from the microprocessor 8085 . it require 5MHz clock frequency for operation. only a crystal which connected easily across two pins of microprocessor can provide this clock.
The '8085' in the 8085 microprocessor is the designation given to the microprocessor by Intel. The '5' means it is a single power supply (5 volt) version of the 8080, with enhancements.
There are 256 ports available in the 8085 microprocessor. The IN and OUT instructions have an 8-bit port number, and that is where the 256 comes from.In order to use ports, the hardware addressing system must decode IO/M-. Some implementations don't do this, so they map IO addresses to memory addresses. In that case, you could say there are 65536 possible IO addresses, but that is not the same as ports, because ports are specific to the IN and OUT instructions.The other "problem" with IN and OUT is that you cannot specify the address in a register, while you can do so with indirect memory addressing.
+5v necessary for microprocessor 8085.
8085 is a 8 bit microprocessor designed by Intel Co.
crystal is a oscilltor in microprocessor
The 8085 is not pipelined.
+5v supply is alone needed for Intel 8085 Microprocessor
program to find prime number in 8085 microprocessor
HL is a register pair used to store 16 bit of data in 8085 microprocessor.
There are 74 instructions in the 8085 microprocessor.