If 8-bits were used to hold one number, the sample range would go from -128 to +127. Since sound samples can be both positive and negative you would use this range instead of the "bit math" 0 to 255. If 8-bits were used to hold one number, the sample range would go from -128 to +127. Since sound samples can be both positive and negative you would use this range instead of the "bit math" 0 to 255.
-128 to +127 is the range of bits
256 is how many samples there are in 8 bits
A byte contains 8 bits. So, a byte can store 2^8 differents values, i.e. 256.
256 (0 through 255)
0.0000001
Yes, a byte is 8 bits, and a one hexadecimal digit takes up four bits, so two hexadecimal digits can be stored in a byte. The largest hexadecimal digit is F (which is 15 in base ten.) In base two, this converts to 1111, which takes up four bits, which is why it only takes four bits to store a hexadecimal digit. With 8 bits, two hexadecimal digits can be stored (FF would be 11111111, which is 8 bits), and 8 bits make up a byte. Generally, 4 bits are always used to store a hexadecimal digit, using leading zeros where necessary. For example, the hexadecimal digit 5 would be stored as 0101, and the hexadecimal digits 5A would be stored as 01011010.
Generally speaking, eight bits to a byte. There is no actual standard that defines how many bits are in a byte, but it has become something of a de facto standard.
8 bits is 0.00097656248 KB
8 bits
8 bits
Characters are typically stored in 8 bits.
8 giga bits of space are available
1 byte=8 bits SO, 3byts=24 bits
1 byte = 8 bits (4096 bytes) x (8 bits/byte) = 32768 bits
8 bits = 64 character