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a 16.7 g polystyrene foam cup containing 31.0 mL coffee changes in temperature from 18 degrees celsius to 66.4 degrees celsius. calculate the heat absorbed by the cup and the coffee?
hint: coffee is made with water express your answer in kJ
30
What else can I help you with?
How do you calculate the heat capacity of a calorimeter containing water?
To calculate the heat capacity of a calorimeter containing water, you can use the formula Q mcT, where Q is the heat absorbed or released, m is the mass of water, c is the specific heat capacity of water, and T is the change in temperature. By measuring the temperature change when a known amount of heat is added or removed from the water in the calorimeter, you can determine the heat capacity of the calorimeter.
Can polystyrene pass UV light?
Polystyrene does not transmit UV light very well as it is a type of plastic that is typically opaque to UV radiation. UV light tends to be absorbed or reflected by the polystyrene material rather than passing through it.
How do you calculate the heat capacity of a bomb calorimeter?
To calculate the heat capacity of a bomb calorimeter, you can use the formula Q C x T, where Q is the heat absorbed or released, C is the heat capacity of the calorimeter, and T is the change in temperature. By measuring the heat absorbed or released and the change in temperature, you can determine the heat capacity of the bomb calorimeter.
How do you calculate the heat capacity of a calorimeter?
To calculate the heat capacity of a calorimeter, you can use the formula Q mcT, where Q is the heat absorbed or released, m is the mass of the substance in the calorimeter, c is the specific heat capacity of the substance, and T is the change in temperature. By measuring the heat absorbed or released and the change in temperature, you can determine the heat capacity of the calorimeter.
How much heat must be absorbed by 50 grams?
Joule (J) is a unit of energy.Gram (g) is a unit for mass.
How many joules are absorbed by the water with a mass of 5kg in orderto risethe temperature from 30 c to 65 c?
To calculate the energy absorbed by the water, you can use the equation Q = mcΔT, where Q is the energy absorbed, m is the mass of water (5kg), c is the specific heat capacity of water (4186 J/kg°C), and ΔT is the change in temperature (65°C - 30°C). Plugging in the values gives Q = 5kg * 4186 J/kg°C * (65°C - 30°C). Calculate this to find the energy absorbed in joules.
How is stoichiometry used to calculate energy absorbed when a mass liquid boils?
Grams liquid × mol/g × Hvap
What is the bomb calorimetry equation used to calculate the heat released or absorbed during a chemical reaction?
The bomb calorimetry equation used to calculate the heat released or absorbed during a chemical reaction is Q mcT, where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity, and T is the change in temperature.
How much heat is absorbed by 100 mL of a dilute slution of NH4NO3 as it changes its temperature from 25.3 to 22.4?
To calculate the heat absorbed, you need the specific heat capacity of the solution. Once you have that, you can use the formula: Q = m * c * ΔT, where Q is the heat absorbed, m is the mass of the solution, c is the specific heat capacity, and ΔT is the change in temperature. Plug in the values and calculate to find the amount of heat absorbed.
What is the process to calculate the specific heat of a calorimeter?
To calculate the specific heat of a calorimeter, you can use the formula q mcT, where q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity, and T is the change in temperature. By measuring the heat absorbed or released and the other variables, you can solve for the specific heat capacity of the calorimeter.
When heat is absorbed does the temperature of the system increase?
When heat is absorbed by a system, the temperature typically increases if the system is not undergoing a phase change and if it has a constant volume. However, during a phase change (such as melting or boiling), the temperature remains constant even as heat is absorbed. The specific heat capacity of the material also influences how much the temperature will rise with absorbed heat.
How much ice in grams would have to melt to lower the temperature of 53.0g of water from 65.0C to 0 C?
To lower the temperature of 53.0g of water from 65.0°C to 0°C, we need to calculate the heat required to cool the water and then use this heat to melt the ice. First, calculate the heat absorbed by the water using the formula: q = mcΔT, where q is the heat, m is the mass, c is the specific heat capacity of water, and ΔT is the temperature change. Then, use the heat absorbed to calculate the amount of ice melted using the heat of fusion of ice (334 J/g).
