Joule (J) is a unit of energy.
Gram (g) is a unit for mass.
To get ice to its melting point, it must absorb 334 joules of energy per gram of ice. So, for 150 grams of ice, the total energy required would be 50,100 joules (334 J/g * 150 g).
The heat required to convert 20 g of liquid water at 100°C to steam at 100°C is the heat of vaporization of water. This is 2260 J/g. Therefore, the total heat required is 20 g * 2260 J/g = 45200 J. This amount of heat is absorbed by the water as it changes phase from liquid to steam.
1 x 10^4 J
To calculate the heat absorbed by the water, you can use the formula ( Q = mc\Delta T ), where ( Q ) is the heat absorbed, ( m ) is the mass of the water, ( c ) is the specific heat capacity of water (approximately 4.18 J/g°C), and ( \Delta T ) is the change in temperature. For a 500 g pot of water raising the temperature from 20°C to 30°C (( \Delta T = 10°C )), the calculation would be: [ Q = 500 , \text{g} \times 4.18 , \text{J/g°C} \times 10 , \text{°C} = 20,900 , \text{J} ] Thus, 20,900 joules of heat must be absorbed.
During a phase change, the heat energy of an object must either be absorbed or released to allow the particles to overcome intermolecular forces and rearrange into a new phase. For example, during melting, heat energy is absorbed to break the intermolecular bonds holding the solid together and transition it into a liquid.
Why does heat get absorbed by the engine must be discharged??The reason why heat is absorbed by the engine must be discharged to the atmosphere in one way or another because the engine will become overheated and eventually seize up and this is why a cooling system is built into the engine to cool it and prevent overheating.This is answered by J.G.NThank you for using this answer in what ever you need it for.
The heat energy required to melt a substance can be calculated using the formula: heat energy = mass * heat of fusion. For water, the heat of fusion is 334 J/g. So for 35.0 grams of water, the heat energy required to completely melt it is 35.0 g * 334 J/g = 11,690 J.
Melt.
it will be 11,700J since the formula would be: q=mHf=35g x 334 J/g= 11,700 J
In calculating the heat given off by a reaction in a calorimeter, you must account for heat absorbed by the surroundings, including the calorimeter itself, any water or solution in the calorimeter, and the air around the calorimeter that may be affected by the reaction. This ensures an accurate measurement of the heat released or absorbed by the reaction itself.
You must first convert kJ/mol. So.. -237kJ x (1kJ / 2.60mol) = -91.15kJ You then must take this and multiple by (-1), since you cannot have a negative heat. (-91.15kJ x -1) = 91.15kJ
You must first convert kJ/mol. So.. -237kJ x (1kJ / 2.60mol) = -91.15kJ You then must take this and multiple by (-1), since you cannot have a negative heat. (-91.15kJ x -1) = 91.15kJ
To get ice to its melting point, it must absorb 334 joules of energy per gram of ice. So, for 150 grams of ice, the total energy required would be 50,100 joules (334 J/g * 150 g).
There are three: Energy absorbed by a body is directly proportional to the rise in temperature of a body Heat energy absorbed by a body is directly proportional to the mass of the body Heat energy absorbed by a body depends upon its nature and is commonly called specific heat capacity.
The heat required to convert 20 g of liquid water at 100°C to steam at 100°C is the heat of vaporization of water. This is 2260 J/g. Therefore, the total heat required is 20 g * 2260 J/g = 45200 J. This amount of heat is absorbed by the water as it changes phase from liquid to steam.
1 x 10^4 J
Boiling does require the liquid to be absorbing heat--large amounts at the point of transition from liquid to gas. Obviously, in the real world, some of this heat is being released simultaneously, but more must be absorbed than is released for boiling to continue.