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How much heat energy must be absorbed to completely melt 35.0 grams of water at 0 degrees Celsius?
The heat energy required to melt a substance can be calculated using the formula: heat energy = mass * heat of fusion. For water, the heat of fusion is 334 J/g. So for 35.0 grams of water, the heat energy required to completely melt it is 35.0 g * 334 J/g = 11,690 J.
What would be the final temperature when 250 grams of water at 100 degrees celsius is mixed with 525 grams of water at 30 degrees celsius?
The final temperature would be approximately 54.2 degrees Celsius. This can be calculated using the principle of conservation of energy, where the heat lost by the hot water is equal to the heat gained by the cold water.
How many grams of kno3 can be dissolved at 50 degrees Celsius?
Approximately 200 grams of KNO3 can be dissolved in 100 ml of water at 50 degrees Celsius.
What is the density of sulfur at twenty five degrees Celsius?
The density of sulfur in grams/cm3 is 2.070. (not at twenty five degrees Celsius)
How many grams of kCL will dissolve in 100 grams of H2O at 10 digrees Celsius?
Learn spelling first, then come back... KCl Degrees Celcius
How much heat energy is absorbed in 65 gram sample whose temperature changed from 45 to 80 degrees celsius?
That completely depends on the specific heat capacity of the substance of which the sample is composed, which you haven't identified. It will take a lot more heat energy to raise the temperature of 65 grams of water 35 degrees than it would take to do the same to 65 grams of iron or yogurt, e.g.
How much energy is absorbed by 50 grams of water if the temperature changes from 22 degrees celsius to 28 degrees celsius?
Change in temp = 28° - 22° = 6°. Heat capacity of liquid water is 1 calorie per gram per degree(C).So the energy absorbed is (50) x (6) = 300 calories.
How many kilojoules of heat are absorbed when 70.00 grams of water is completely vaporized at its boiling point?
158.1Kj
How much heat energy must be absorbed to completely melt 35.0 grams of water at 0 degrees Celsius?
The heat energy required to melt a substance can be calculated using the formula: heat energy = mass * heat of fusion. For water, the heat of fusion is 334 J/g. So for 35.0 grams of water, the heat energy required to completely melt it is 35.0 g * 334 J/g = 11,690 J.
How is Stoichiometry use to calculate energy absorbed when a mass of liquid boils?
Grams liquid × mol/g × Hvap
How is stoichiometry used to calculate energy absorbed when mass of solid melts?
Grams solid × mol/g × Hfusion
How much energy must be absorbed by 150 grams of ice?
To get ice to its melting point, it must absorb 334 joules of energy per gram of ice. So, for 150 grams of ice, the total energy required would be 50,100 joules (334 J/g * 150 g).
How is stoichiometry used to calculate energy absorbed when a mass liquid boils?
Grams liquid × mol/g × Hvap
How much energy is absorbed when 356 g of ethanol 46.0 g molboils The heat of vaporization of ethanol is 38.6 kJ mol?
To calculate the energy absorbed, first convert the mass of ethanol from grams to moles. 356 g of ethanol is 356/46.0 = 7.74 moles. Then, multiply the moles of ethanol by the heat of vaporization: 7.74 mol * 38.6 kJ/mol = 298.56 kJ of energy absorbed.
What has more thermal energy one gram of water at 75 degrees or 100 grams of water at 75 degrees?
(75'C)x(1g) < (75'C)x(100g) .'. The second option has more thermal energy.
How many joules are absorbed by the water with a mass of 8 kg in order to raise the temperature from 20 degrees to 70 degrees?
q(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams ) q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C) = 1.7 X 106 joules ============
How many calories would be needed to melt 10 grams of ice at 0 degrees C?
To melt 10 grams of ice at 0 degrees Celsius, it would require 80 calories of heat energy per gram, so a total of 800 calories (80 calories/gram * 10 grams = 800 calories) would be needed.
