answersLogoWhite

0


Best Answer

it will be 11,700J

since the formula would be:

q=mHf=35g x 334 J/g= 11,700 J

User Avatar

Wiki User

10y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How much heat energy must be absorbed to completely melt 35 grams of h2o at o degrees?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How much heat energy is absorbed in 65 gram sample whose temperature changed from 45 to 80 degrees celsius?

That completely depends on the specific heat capacity of the substance of which the sample is composed, which you haven't identified. It will take a lot more heat energy to raise the temperature of 65 grams of water 35 degrees than it would take to do the same to 65 grams of iron or yogurt, e.g.


How much heat energy must be absorbed to completely melt 35.0 grams of water at 0 degrees Celsius?

Ice at 0 deg C has a latent heat of melting of 335 kJ/kg. If you have 35 grams (0.035 kg), then it would take exactly 11.725 kJ to melt the ice to get 35 grams of water at 0 deg C.


How much energy is absorbed by 50 grams of water if the temperature changes from 22 degrees celsius to 28 degrees celsius?

Change in temp = 28° - 22° = 6°. Heat capacity of liquid water is 1 calorie per gram per degree(C).So the energy absorbed is (50) x (6) = 300 calories.


How many kilojoules of heat are absorbed when 70.00 grams of water is completely vaporized at its boiling point?

158.1Kj


How is stoichiometry used to calculate energy absorbed when mass of solid melts?

Grams solid × mol/g × Hfusion


How is stoichiometry used to calculate energy absorbed when a mass liquid boils?

Grams liquid × mol/g × Hvap


How is Stoichiometry use to calculate energy absorbed when a mass of liquid boils?

Grams liquid × mol/g × Hvap


What has more thermal energy one gram of water at 75 degrees or 100 grams of water at 75 degrees?

(75'C)x(1g) < (75'C)x(100g) .'. The second option has more thermal energy.


How many joules are absorbed by the water with a mass of 8 kg in order to raise the temperature from 20 degrees to 70 degrees?

q(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams ) q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C) = 1.7 X 106 joules ============


How many joules of heat energy must be supplied to 21 g of water to raise the temperature of the water from 24 to 95 degrees Celsius?

21 grams through 71 degrees is 21x71 calories.


How many grams of water were involved if a mass of water dropped in temperature by 25.1 degrees celcius. It gave off 5240.0J of energy in the process.?

k


How many grams of antimatter are needed to react with 5 g of matter?

Exactly 5 grams of antimatter will completely annihilate 5 grams of matter, producing an enormous shower of high energy gamma rays. In total a mass of 10 grams will be converted to the equivalent amount of energy.