The temperature would be that of water's boilng point od 100 degrees
Learn spelling first, then come back... KCl Degrees Celcius
The solubility of NaCl in water at 0 degrees Celsius is approximately 35.7 grams per 100 grams of water. This means that at this temperature, 100 grams of water can dissolve 35.7 grams of NaCl before reaching saturation.
I believe it will be 145.52 degrees Celsius if I did my math correctly. You need to convert calories to joules. I believe one joule raises the temp of 1 gram water by 1 degree Celsius so 1200*4.184=5020.8 J /40grams=125.52 temp increase+20=145.52 degrees Celsius.
The density of sulfur in grams/cm3 is 2.070. (not at twenty five degrees Celsius)
The density of water at 37 degrees Celsius is around 0.988 grams per cubic centimeter. At this temperature, water is slightly less dense compared to when it is at 4 degrees Celsius, where it has a density of 1.000 grams per cubic centimeter.
The final temperature is 59.9°C.
Approx 4974 Joules.
No, grams are unit of mass, not temperature. Temperature is measured in °C (degrees celsius) or for scientific work in 'K' K = °C + 273.15
105C
Density of ice at 0 degrees Celsius is 916.8 grams per cubic centimeter or milliliter. The density of fresh water is dependant on the temperature: At 3.98 degrees Celsius the density is 0.999975 grams per milliliter. At 100 degrees Celsius the density is 0.958.35 grams per milliliter.
Learn spelling first, then come back... KCl Degrees Celcius
At -20 degrees Celsius, the saturation vapor pressure of water is about 2.2 millibars. Therefore, to saturate a kilogram of air at this temperature, you would need about 2.2 grams of water vapor.
The density of pure water at 97 degrees Celsius is approximately 0.971 grams per cubic centimeter. At this temperature, water is less dense compared to at 4 degrees Celsius (which is the temperature at which water has its highest density).
The solubility of NaCl in water at 0 degrees Celsius is approximately 35.7 grams per 100 grams of water. This means that at this temperature, 100 grams of water can dissolve 35.7 grams of NaCl before reaching saturation.
The final equilibrium temperature can be found using the principle of conservation of energy. The heat lost by the coffee as it cools down is equal to the heat gained by the milk as it warms up. Using the formula Q = mcΔT, where Q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, you can calculate the final temperature.
I believe it will be 145.52 degrees Celsius if I did my math correctly. You need to convert calories to joules. I believe one joule raises the temp of 1 gram water by 1 degree Celsius so 1200*4.184=5020.8 J /40grams=125.52 temp increase+20=145.52 degrees Celsius.
Liters measure volume. Grams are a measure of mass, degrees Celsius are a measure of temperature, and meters are a measure of length.