I believe it will be 145.52 degrees Celsius if I did my math correctly. You need to convert calories to joules. I believe one joule raises the temp of 1 gram water by 1 degree Celsius so 1200*4.184=5020.8 J /40grams=125.52 temp increase+20=145.52 degrees Celsius.
To find the final temperature, we can use the principle of conservation of energy: heat lost by gold = heat gained by water. We can use the formula m * c * ∆T to calculate the heat exchanged. By setting the two heat exchanges equal to each other and solving for the final temperature, we can find that the final temperature is 25.9 degrees Celsius.
I must assume that the ice block is at an initial temperature of 0o C. I also need to work in joules,. so I will convert the calories to joules. 1600 cal. (4.184 joule/1 cal.) = 6694.4 joules -------------------- 6694.4 J = (20 grams H2O)(4.180 J/gC)(Tf - 0o C) 6694.4/83.6 = Tf = 80o Celsius ==========
Turn 367.67 K to 94.52 Celsius Use........ q(joules) = mass * specific heat * change in temperature 8615 J = 23.31 g * 4.180 J/gC * (Tf - 94.52 C) 8615 = 111.888Tf -10575.65376 19190.65376 = 111.888Tf 171.5 Celsius final temp.
To find the net amount of cargo loaded, you need to consider the expansion of the gasoline due to the change in temperature. Since the coefficient of expansion is 0.0008 per degree Celsius, you can calculate the increase in volume of the gasoline when it heats up from 27 degrees Celsius to its final temperature. You can then subtract this increase in volume from the initial volume to find the net amount of cargo loaded.
The final temperature would be approximately 54.2 degrees Celsius. This can be calculated using the principle of conservation of energy, where the heat lost by the hot water is equal to the heat gained by the cold water.
1600
The final temperature can be calculated using the principle of conservation of energy. The heat gained by the cooler water is equal to the heat lost by the warmer water. The final temperature is the temperature at which this heat exchange occurs, which can be calculated using the formula for heat transfer.
This depends on the volume.
No, as both the temperatures are the same, you will get only 2 cups, each 50 degrees. You have to heat the cup to get 100 degree.
The final temperature of the mixture will be between 5 and 20 degrees Celsius, closer to 5 degrees since a larger mass of water is at that temperature. To find the exact final temperature, you can use the principle of conservation of energy (Q lost = Q gained).
42.3 C
The change in temperature is +39 degrees Celsius, as the final temperature (23°C) is higher than the initial temperature (-16°C). Elevation is not relevant in this context since it remains constant.
To find the final temperature, you can use the equation: q = mcΔT, where q is the heat added, m is the mass, c is the specific heat capacity of aluminum, and ΔT is the change in temperature. Rearrange the equation to solve for final temperature, T. Substitute the values and solve for T.
This is the formula for finding calories: calories= (Tf-Ti)mass Or, in words, you subtract the final temperature (the temperature of the fused waters) by its initial temperature (the hot/ cold water's original temperature). You then multiply this answer by the mass of the water before you mix them together. Your hot and cold water should both have the same mass, but not the same temperature.
I need to make some conversions for my own convenience. 750 calories (4.184 Joules/1 calorie) = 3138 Joules ----------------------- Lead specific heat (c) = 0.160 J/gC Now, q = mass * specific heat * change in temperature 3138 Joules = (250 g Pb)(0.160 J/gC)(Tf - 28.0 C) 3138 J = 40Tf- 1120 4258 = 40Tf 106 Celsius = Final temperature of lead ----------------------------------------------------
Time table for degree final years?
60