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I believe it will be 145.52 degrees Celsius if I did my math correctly. You need to convert calories to joules. I believe one joule raises the temp of 1 gram water by 1 degree Celsius so 1200*4.184=5020.8 J /40grams=125.52 temp increase+20=145.52 degrees Celsius.

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What is the final temperature of a 3.0kg bar of gold at 99 degrees Celsius dropped into 0.22kg of water at 25 degrees celsius?

To find the final temperature, we can use the principle of conservation of energy: heat lost by gold = heat gained by water. We can use the formula m * c * ∆T to calculate the heat exchanged. By setting the two heat exchanges equal to each other and solving for the final temperature, we can find that the final temperature is 25.9 degrees Celsius.


What will be the final temperature if 1600 cal of heat is given to an ice block of mass 20 grams?

I must assume that the ice block is at an initial temperature of 0o C. I also need to work in joules,. so I will convert the calories to joules. 1600 cal. (4.184 joule/1 cal.) = 6694.4 joules -------------------- 6694.4 J = (20 grams H2O)(4.180 J/gC)(Tf - 0o C) 6694.4/83.6 = Tf = 80o Celsius ==========


A sample of water with a mass of 23.31g and an initial temperature of 367.67 k loses 8615 joules What is the final temperature?

Turn 367.67 K to 94.52 Celsius Use........ q(joules) = mass * specific heat * change in temperature 8615 J = 23.31 g * 4.180 J/gC * (Tf - 94.52 C) 8615 = 111.888Tf -10575.65376 19190.65376 = 111.888Tf 171.5 Celsius final temp.


A tank is loaded with 9000 barrel of gasoline The temperature of the product is 27 degrees Celsius and it has the coefficient of expansion of 0008 The net amount of cargo loaded is?

To find the net amount of cargo loaded, you need to consider the expansion of the gasoline due to the change in temperature. Since the coefficient of expansion is 0.0008 per degree Celsius, you can calculate the increase in volume of the gasoline when it heats up from 27 degrees Celsius to its final temperature. You can then subtract this increase in volume from the initial volume to find the net amount of cargo loaded.


What would be the final temperature when 250 grams of water at 100 degrees celsius is mixed with 525 grams of water at 30 degrees celsius?

The final temperature would be approximately 54.2 degrees Celsius. This can be calculated using the principle of conservation of energy, where the heat lost by the hot water is equal to the heat gained by the cold water.

Related Questions

If 1500 calories are added to 100 degrees celsius what will the final temperature of the steam be?

1600


What is the final temperature of 50ml of 50 degree C water mixed with 50ml of 10 degree C.?

The final temperature can be calculated using the principle of conservation of energy. The heat gained by the cooler water is equal to the heat lost by the warmer water. The final temperature is the temperature at which this heat exchange occurs, which can be calculated using the formula for heat transfer.


What is the final temperature of a 20 degree Celsius room temperature pool of water following addition of 960 kJ of energy?

This depends on the volume.


If a cup of water of temperature 50 degree celsius is mixed with another cup of water of temperature 50 degree celsius the final temperature of the two combined cups of water will be 100 degree?

No, as both the temperatures are the same, you will get only 2 cups, each 50 degrees. You have to heat the cup to get 100 degree.


100 g of water at 20 degree centigrade is mixed with 100 g of water at 5 degree centegrade the temperature of mixture will be?

The final temperature of the mixture will be between 5 and 20 degrees Celsius, closer to 5 degrees since a larger mass of water is at that temperature. To find the exact final temperature, you can use the principle of conservation of energy (Q lost = Q gained).


What is the final temperature of a 48.26 g sample of aluminum at 100 degree Celsius dripped into 34.47 g of water at 25.0 degree Celsius?

42.3 C


Find the change in temperature or elevation from -16 degree celecius to 23 degree Celsius?

The change in temperature is +39 degrees Celsius, as the final temperature (23°C) is higher than the initial temperature (-16°C). Elevation is not relevant in this context since it remains constant.


A 4.0-kg aluminum block is originally at 10 o C If 160 kJ of heat is added to the block what is its final temperature?

To find the final temperature, you can use the equation: q = mcΔT, where q is the heat added, m is the mass, c is the specific heat capacity of aluminum, and ΔT is the change in temperature. Rearrange the equation to solve for final temperature, T. Substitute the values and solve for T.


Can you give some mathematical problems related to heat of fusion?

This is the formula for finding calories: calories= (Tf-Ti)mass Or, in words, you subtract the final temperature (the temperature of the fused waters) by its initial temperature (the hot/ cold water's original temperature). You then multiply this answer by the mass of the water before you mix them together. Your hot and cold water should both have the same mass, but not the same temperature.


How 750 calories of heat are added to 250 grams of Lead c equals 0.031 cal g C initially at a temperature of 28.0 C What will be the final temperature of this piece of Lead?

I need to make some conversions for my own convenience. 750 calories (4.184 Joules/1 calorie) = 3138 Joules ----------------------- Lead specific heat (c) = 0.160 J/gC Now, q = mass * specific heat * change in temperature 3138 Joules = (250 g Pb)(0.160 J/gC)(Tf - 28.0 C) 3138 J = 40Tf- 1120 4258 = 40Tf 106 Celsius = Final temperature of lead ----------------------------------------------------


Time table for degree final years?

Time table for degree final years?


When an equal volume of 40 degrees celsius is added to a 20 degree celsius container what will the temperature be?

60