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Using PV=nRT, 10.0ºC = 283.15ºK, R = 62.36 L torr/mol K

V= (nRT)/P

V = (2.35m*(62.36 L torr/mol K)*283.15ºK)/766.7 Torr

V = 54.12 L

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Marcus Rivera

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Q: A gas has a pressure of 766.7 torr at a temperature of 10.0°C. the sample contains 2.35 moles of xenon. what is the volume of the gas in liters?
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