A pretty bow
100%
The offspring will all inherit one copy of the dominant allele (from the heterozygous parent) and one copy of the recessive allele (from the homozygous recessive parent). This results in all offspring being heterozygous for the trait.
100% of the offspring will display the dominant trait because the homozygous dominant parent can only pass on the dominant allele. The offspring will inherit one dominant allele from the dominant parent and one recessive allele from the recessive parent, resulting in a heterozygous genotype expressing the dominant trait.
Out of the 240 offspring, approximately 60 would be homozygous (25% of 240). This is because when two heterozygous plants are crossed (Aa x Aa), the Punnett square shows that 25% of the offspring will be homozygous dominant (AA), 50% will be heterozygous (Aa), and 25% will be homozygous recessive (aa).
The possible genotypes of parents who are heterozygous would be found using a punnet square. The outcome would be 50 percent heterozygous dominant, 25 percent homozygous dominant, and 25 percent homozygous recessive.
In a testcross, an individual with a dominant phenotype but unknown genotype is crossed with an individual that is homozygous recessive for the same trait. This helps determine the unknown genotype of the dominant individual based on the phenotypic ratios of the offspring. If any offspring display the recessive phenotype, it indicates that the dominant parent is heterozygous. Conversely, if all offspring show the dominant phenotype, the dominant parent is likely homozygous.
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
The offspring would have a 50% chance of being heterozygous and showing the dominant trait and a 50% chance of being homozygous for the recessive trait.
A dominant trait will appear in offspring that inherits at least one copy of the dominant allele from either parent. If an individual has two different alleles for a trait (one dominant and one recessive), the dominant trait will be expressed.
The homozygous recessive individual is used in a test cross to determine the genotype of an individual with a dominant phenotype but unknown genotype. When crossed with a homozygous recessive individual, if any offspring display the recessive trait, it indicates that the unknown individual is heterozygous for that trait.
If you cross a homozygous dominant individual (AA) with a heterozygous individual (Aa), the offspring will have a genotype ratio of 100% dominant phenotype (AA or Aa) and 0% recessive phenotype (aa). Therefore, if your offspring has a homozygous dominant trait (AA), the likelihood of expressing a recessive trait (aa) is 0%. The Punnett square for this cross would show all dominant traits, confirming that recessive traits cannot be expressed in this scenario.
In genetics, you can either have a dominant allele (A) or a recessive allele (a). Being homozygous means that you have both of either a dominant or a recessive allele (ie you are either AA or aa). If the trait is a recessive trait, then you need to have it be homozygous recessive in order to express that trait. Hope this was helpful! :-)