The offspring would have a 50% chance of being heterozygous and showing the dominant trait and a 50% chance of being homozygous for the recessive trait.
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
of two different phenotypes
All the offspring will be heterozygous with a phenotype showing the dominant trait. Let the alleles be H (dominant) and h (recessive). All the gametes from the first individual will be H, and from the other, h. Thus all the offspring must be Hh.
The probability that an individual heterozygous for a cleft chin and an individual homozygous for a chin without a cleft will produce offspring that are homozygous recessive for a chin without a cleft is fifty percent. You can calculate this by making a Punnet square.
A cross between a homozygous recessive and an individual of unknown genotype is called a test cross.The homozygous recessive can only pass on a recessive allele to the offspring, and so any recessive in the other parent will show up in the phenotype (detectable characteristics) of some of the offspring.
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
The offspring has a 50% chance of the dominate trait (while being heteroygous) and a 50% chance of having the recessive trait ( homozygous recessive).
of two different phenotypes
Their offspring will be heterozygous recessive.
The homozygous dominant individual can only pass on the dominant allele and the homozygous recessive individual can only pass on the recessive allele, therefore all offspring will be heterozygous and have the dominant phenotype.
All the offspring will be heterozygous with a phenotype showing the dominant trait. Let the alleles be H (dominant) and h (recessive). All the gametes from the first individual will be H, and from the other, h. Thus all the offspring must be Hh.
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
The probability that an individual heterozygous for a cleft chin and an individual homozygous for a chin without a cleft will produce offspring that are homozygous recessive for a chin without a cleft is fifty percent. You can calculate this by making a Punnet square.
Heterozygous induviduals pass the dominant and recessive alleles to offspring
A cross between a homozygous recessive and an individual of unknown genotype is called a test cross.The homozygous recessive can only pass on a recessive allele to the offspring, and so any recessive in the other parent will show up in the phenotype (detectable characteristics) of some of the offspring.
A living thing with a dominant and a recessive gene for a trait is heterozygous. This individual will display the dominant phenotype for that trait but may have offspring that display the recessive trait.
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.