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A stone is thrown upward at 27 m/s from a cliff that is 125m relative to the sea? How long will it take to hit the water

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A stone is thrown upward at 27 m/s from a cliff. How long will it take to hit the water?

Well, if a rock is throws 27m into the air, it will probably reach the water faster than 27m because of gravity.


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The velocity decreases as the stone moves upward due to the force of gravity acting in the opposite direction of the motion. Gravity slows down the stone's speed, eventually bringing it to a stop at the highest point before it starts to fall back down.


A stone is thrown straight upward and it rises to a height of 20 meters With what speed was it thrown?

To determine the initial speed, you can use the kinematic equation: v² = u² + 2as, where v is the final velocity (0 m/s at the top), u is the initial velocity, a is acceleration (gravitational acceleration at -9.8 m/s²), and s is the displacement (20 m). Solving for u, you get u = sqrt(2as) = sqrt(2*-9.8*20) = 19.8 m/s. So, the stone was thrown upward with a speed of 19.8 m/s.


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