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What happens when two identical balls are thrown directly upward?
When two identical balls are thrown directly upward, they will follow the same path and reach the same height before falling back down due to gravity.
What is the acceleration of a ball at the top of its trajectory when thrown straight upward?
The acceleration of a ball at the top of its trajectory when thrown straight upward is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 downward. At the top of its trajectory, the ball momentarily comes to a stop before reversing direction and accelerating downward.
What is tje velocity of a ball thrown upward at 16 ft/sec?
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
What is the velocity of a ball thrown upward at 16 feetsec?
The velocity of the ball is 16 feet/sec when it is thrown upward.
How much work is done when an object is thrown upward?
When an object is thrown upward, work is done against gravity as the object moves upward. The amount of work done is equal to the force applied to lift the object multiplied by the distance it moves vertically.
How long will it take the ball to return to earth when it is thrown straight upward at 150' per second at the height of 5'?
OW! Not long enough!
What happens when two identical balls are thrown directly upward?
When two identical balls are thrown directly upward, they will follow the same path and reach the same height before falling back down due to gravity.
What is the height of a rock that is thrown upward with an initial speed of 15 meter per second?
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
What is the acceleration of a ball at the top of its trajectory when thrown straight upward?
The acceleration of a ball at the top of its trajectory when thrown straight upward is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 downward. At the top of its trajectory, the ball momentarily comes to a stop before reversing direction and accelerating downward.
What is tje velocity of a ball thrown upward at 16 ft/sec?
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
Acceleration of a rock thrown straight upward at the moment it reaches the tippy-top of its trajectory?
9.8 m/s (2) Squared
What is the velocity of a ball thrown upward at 16 feetsec?
The velocity of the ball is 16 feet/sec when it is thrown upward.
How is it that A ball is projected straight up from the ground with a speed of 7.61 meters per second To what maximum height will the ball go when gravity equals 9.80 meters per second squared?
Initial upward speed = 7.61 m/sFinal upward speed (at the point of maximum height) = 0Time to reach maximum height = (7.61) / (9.8) = 0.77653 secondAverage speed during that time = 1/2 ( 7.61 + 0) = 3.805 m/sHeight = 3.805 x 0.77653 = 2.9547 meters (rounded) = about 9.7 feetDoesn't seem like much of a height for a strong toss; but the math looks OK.
How much work is done when an object is thrown upward?
When an object is thrown upward, work is done against gravity as the object moves upward. The amount of work done is equal to the force applied to lift the object multiplied by the distance it moves vertically.
What happened to the ball when you thrown upward?
When a ball is thrown upward, it experiences a brief period of acceleration while moving against the force of gravity. Once the ball reaches its peak height, it begins to fall back down due to gravity.
A ball thrown upward reaches 13 meters how much time will it take to fall to the ground?
t matters how much mass the ball has
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
