There is no exit instruction in the 8085. Do you mean return, as in from a function or interrupt? If so, the instruction is RET.
Not in the 8085.
There are 74 instructions in the 8085 microprocessor.
this instruction is used to add the specified register content to that of the accumulator along with the carry flag value. this instruction is used in processes which involve continuous addition.
MUL is not an 8085 instruction.
The accumulator is a general register that holds a value. It is also a special register that can be used as the target for the result of various arithmetic or logical computations. For instance, if you wanted to add two numbers, you could load the first into the accumulator, add the second to the accumulator, and then store the accumulator where wanted. The instruction register is an internal register that holds the value of the instruction opcode in order for the 8085 to decode and process the instruction. While it is shown on the Intel block diagram for the 8085, it is not directly accessible by the running program - it is for internal use only by the 8085.
Examples: /360: no accumulator 8080: A 6800: A and B 8086: AX ...
CALL, requiring 18 clock cycles.
There are 74 instructions in the 8085 microprocessor.
Suppose you want to add 11 and 12.instruction are : mvi a,11h mvi b ,12h mov d,b add b
The NOP instruction is a no-operation instruction. It does nothing to the state of the machine, except to use some time. In the case of the 8085, it uses four clock cycles plus however many wait states are need to access the NOP instruction from memory.
There are no instructions in the 8085 that execute in only one clock pulse. The minimum number of clock cycles is four; three for instruction fetch and one for instruction decode/execute.