There is a 3.75 Volt drop across each bulb.
To find the net resistance of the circuit connected to the battery in the figure, you need to calculate the total resistance by adding up the individual resistances in the circuit.
The net resistance of the circuit connected to the battery in Figure 1 is the total resistance that the current encounters when flowing through the circuit. It is calculated by adding up the individual resistances of all the components in the circuit.
The resistance of the load is what causes an electric current to flow in a circuit.
Related to a battery and open load is the battery just sitting there without anything connected. A short is a very low resistance attached to the tow terminals of the battery. For example, a wire connected across the battery terminals would constitute a short.
Nothing will happen. There has to be a complete a circuit for the battery to function thus allowing for the flow of electricity.
Real-world batteries do not have zero internal resistance. When one connects a load (resistance) to a battery, current begins to flow and the open-circuit potential is divided between the battery's internal resistance and the resistance of the load. Thus, one will measure a lower voltage at the battery terminals when a load is connected, compared to no-load conditions.
The voltage of the battery, and the resistance of the circuit (including the resistance of the wire and the internal resistance of the battery).
4.8 ohms
This circuit is a series circuit, as the current flows sequentially through resistor 1, then through resistor 2, before returning to the battery. The same current passes through both resistors, and the total resistance is the sum of their individual resistances. The voltage across the circuit is divided between the two resistors according to their resistance values. Additionally, if one resistor fails, the entire circuit will be interrupted, stopping the current flow.
The current depends on what is connected to the battery's terminals. If nothing is connected to it, then there is no current, and the battery lasts quite a while. In general, the current is 1.5/resistance of the external circuit connected to the battery until that number gets too big, and then the voltage of the battery sags, because it can't deliver that much current.
A battery produces electricity through a chemical reaction that occurs inside it. When the battery is connected to a circuit, the reaction causes electrons to flow from one terminal to the other, creating an electric current. This flow of electrons is what we perceive as electricity.
If additional resistance is connected in parallel with a circuit the supply voltage will decrease?