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mass Fe * Specific heat Fe* T=Q Q/( Specific Heat water*mass water)= temp change of water so... 4kg(.450 kJ/kg*C)(250C)= 3kg(4.184)T T=35.85 C That help?

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Q: A 3 kg iron bar at 250 degrees Celsius is placed in 4 liters of water at 22.7 degrees Celsius what will be the change in temperature of the water?
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