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A 5 kg book falls from a shelf. If it lands with a speed of 5.7 ms from what height did it fall?
Wiki User
∙ 7y ago
Here is one way to solve it:* Calculate the kinetic energy related to this speed.
* Assume that no mechanical energy was lost; i.e., calculate the height required to get the same gravitational potential energy. That is, write the equation for gravitational potential energy, replace the numbers you know (including the energy you just calculated in the previous point), and calculate the height.
Note that the result does not depend on the mass of the falling object.
Wiki User
∙ 7y ago
Wiki User
∙ 7y agoThe kinetic energy just as it hits the floor will be very close to the potential energy when it is on the shelf. Because on the shelf, all of the energy is potential, and at the floor level it is all kinetic. A small amount will be lost to frictional drag, but it will not affect the outcome, much.
So we have m*g*h = (1/2)*m*v^2. Divide both sides by m, and by g, so we have:
h = (1/2)*(v^2)/g = 1.66 meters
Wiki User
∙ 7y agoheight = 1/2 gravity acceleration (g) x time squared and velocity (v) = acceleration x timetime = v/g = 0.58 secs where g = 9.81 m/s/sheight = 1.65 meters
Wiki User
∙ 6y agoIt fell from approx 1.66 metres. The mass of the book is irrelevant except to confirm that it was massive enough not to be significantly affected by air resistance.
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