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A 60kg platform is 8m wide supported by 4 legs each of which are 2m from the edge of the platform What is the force on the left legs if a 30kg mass is placed on the left edge of the platform?
Wiki User
∙ 13y ago
This problem asks to solve for unknown forces when an object is in equilibrium. Let us solve it!
As platform is in equilibrium , so , by 1st condition of equilibrium,
Upward forces = Downward forces
T1+T2=600+300=900N ,
Now apply second condition,
Anti-clockwise torque= Clockwise torque
(taking point of first leg as axis of rotation so that torque due to T1 is zero)
300*2+T2*4=600*2
600-1200=-T2*4,
600=T2*4, or
T2=600/4=150N ,now
T1=90-T2=900-150=750N
Wiki User
∙ 13y ago
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