This problem asks to solve for unknown forces when an object is in equilibrium. Let us solve it!
As platform is in equilibrium , so , by 1st condition of equilibrium,
Upward forces = Downward forces
T1+T2=600+300=900N ,
Now apply second condition,
Anti-clockwise torque= Clockwise torque
(taking point of first leg as axis of rotation so that torque due to T1 is zero)
300*2+T2*4=600*2
600-1200=-T2*4,
600=T2*4, or
T2=600/4=150N ,now
T1=90-T2=900-150=750N
30kg = 30kg.
3 tenths of 30kg = 3/10 * 30kg = 9kg
To find out how many fifths are in 30kg, you first need to determine the value of one fifth of 30kg. One fifth of 30kg is calculated by dividing 30 by 5, which equals 6kg. Therefore, there are 6kg in one fifth of 30kg.
30kg is equal to approximately 66 pounds.
It is extremely unlikely that you will find 2 men of 30 kg!
Work = Force x DistanceForce = Mass X Gravity (Near earth approximation)SoWork = 30kg x 9.8 m/s2 x 20m = 5880 joules
20% of 30kg= 20% * 30= 0.2 * 30= 6kg
If an object has a mass of 30 kg, its mass on Earth would also be 30 kg. Mass is a measure of the amount of matter in an object, and it remains the same regardless of the gravitational force acting on it.
If two men are applying forces in different directions on a 30kg stone, the resultant force will be the vector sum of the forces applied. If five healthy men are all applying full force on the same stone, the resultant reaction will be greater due to the increased total force applied. The direction of the resultant reaction will depend on the directions of the individual forces.
The answer is 30kg
Honey, a tiger is definitely not 30kg, that's like saying a Big Mac is a health food. A fully grown tiger can weigh up to 300kg, which is basically the weight of a small car. So, if you see a 30kg tiger, you might want to run because that's one skinny cat.
That would be 22.5kg.