V = IR
Voltage = Current * Resistance
so
9 = 0.25 * R
Hence R =36 Ohms
Because they have internal resistance. Current flow through this internal resistance produces heat, just like current flow through ordinary resistors does. The current can be from use of the battery or charging the battery (if it is rechargeable). Usually the internal resistance of a battery increases with age, meaning older batteries tend to run hotter than fresh ones.
The wire acted as the load across the battery terminals. Small short pieces of wire have a very low resistance. Ohms law states I = E/R. Current is directly proportional to the voltage and inversely proportional to the resistance of the circuit. So in other words if the resistance goes low the current (amperage goes high) It is this high current flowing through the wire that makes the wire hot. The higher the resistance the less of a current flow through the wire.
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
A battery contains a charge of electrons. When these electrons leave the battery and travel through a circuit that is described as current.
The amount of current that will pass through a resistance is dependant upon the voltage applied across the resistance. Voltage devided by resistance equals current. This is Ohm's Law.
Your current will be 30/R Amps. Where R is the resistance in Ohms.
The formula you are looking for is R = E/I. Resistance is stated in ohms.
If a battery is "shorted", meaning that its terminals are connected together through a low resistance, high current flows in the connection and the battery becomes discharged very soon. It makes no difference whether any part of the battery is connected to ground.
it determines how well the current flows through the wires. ANSWER: When there is no outside power connected to it. But some power is necessary to read the resistance so the meter battery will supply the current necessary to measure the IR drop and translate that to resistance
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
in voltmeter we have internal Resistance and connected in series , to current don't transfer in voltmeter , and we have internal resistance in ammeter and connected in parallel , to most current transfer through the ammeter.
Ohm's Law: V = IR (voltage = current times resistance).Ohm's Law: V = IR (voltage = current times resistance).Ohm's Law: V = IR (voltage = current times resistance).Ohm's Law: V = IR (voltage = current times resistance).
A shunt resistance is a low resistance connected parallel to the galvanometer so that a large portion of current passes through the low resistance and a small fraction of current passes through the galvanometer this saves the galvanometer from damage
V = I * R. 1.5 = 8*IThe current flow is 3/16 Amps.
If 3 identical 45-ohm resistors are connected in parallel, the net effective resistance of the bunch ...and the load seen by the battery ... is 15 ohms. The current supplied by the battery is60/15 = 4 Amperes.(This assumes that the battery is capable of supplying 4 amps at 60 volts, or 240 watts !)
Because they have internal resistance. Current flow through this internal resistance produces heat, just like current flow through ordinary resistors does. The current can be from use of the battery or charging the battery (if it is rechargeable). Usually the internal resistance of a battery increases with age, meaning older batteries tend to run hotter than fresh ones.
The wire acted as the load across the battery terminals. Small short pieces of wire have a very low resistance. Ohms law states I = E/R. Current is directly proportional to the voltage and inversely proportional to the resistance of the circuit. So in other words if the resistance goes low the current (amperage goes high) It is this high current flowing through the wire that makes the wire hot. The higher the resistance the less of a current flow through the wire.