The objective is to calculate the final velocity of 22.8m/s.
We can use the formula v = u+at
v is th final velocity
u is the initial velocity which is equal to 0 in this case
a=9.8m/s2( given)
t is the time for achieving the final velocity
22.8 = 0+9.8 t
t=22.8/9.8
t=2.3 seconds
It depends on how height the cliff is. I could figure it out if you told me how height the cliff is.
The acceleration of gravity is 9.8 meters/sec2.In 1.5 seconds after it's dropped, any object is falling at (9.8 x 2) = 19.6 meters/sec.The mass of the rock makes no difference.
Yes. Every body that is falling, (if there is no other force then the gravity force) will fall in constant acceleration. Mass does not affect the acceleration of the body. According to Newton's second law: F=m*a m*g=m*a g=a F= Force m= mass a= acceleration g= gravity acceleration m*g= the force of gravity
By moving an object higher up. A ball dropped off a 100 foot cliff has higher potential energy than a ball dropped off a 4 foot tall desk.
Weight is felt by the body resisting the pull (acceleration) of gravity. Less acceleration means less pull thus less weight. The rate at which you are accelerating downward subtracts from the pull of gravity, thus your weight is less. If you fall, say from a cliff or tall building you accelerate downward at exactly the acceleration of gravity so you're completely weightless.
29.4/3=9.8m/s2
176.4 meters
240 ft
The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s
Using the formula s = ut + 1/2at2, where s is the distance travelled, u is the initial velocity, a is the acceleration and t is the time , then :-s = 0 + [1/2 x 9.8 x (9.36)2] = 429.29 meters (2dp)The cliff is 429.29 meters high.
It depends on how height the cliff is. I could figure it out if you told me how height the cliff is.
The acceleration of gravity is 9.8 meters/sec2.In 1.5 seconds after it's dropped, any object is falling at (9.8 x 2) = 19.6 meters/sec.The mass of the rock makes no difference.
speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s
Yes, yes it does.
balls dropped right off as cliff
Yes. Every body that is falling, (if there is no other force then the gravity force) will fall in constant acceleration. Mass does not affect the acceleration of the body. According to Newton's second law: F=m*a m*g=m*a g=a F= Force m= mass a= acceleration g= gravity acceleration m*g= the force of gravity
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