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The objective is to calculate the final velocity of 22.8m/s.

We can use the formula v = u+at

v is th final velocity

u is the initial velocity which is equal to 0 in this case

a=9.8m/s2( given)

t is the time for achieving the final velocity

22.8 = 0+9.8 t

t=22.8/9.8

t=2.3 seconds

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Q: A ball is dropped from a cliff and has acceleration of 9.8ms2 How long will it take the ball to reach a speed of 22.8ms?
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A person on a very high cliff throws a ball vertically up at an initial speed of 13.0 ms Neglect friction whats the speed at the highest point the acceleration at the highest point?

It depends on how height the cliff is. I could figure it out if you told me how height the cliff is.


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Related questions

A ball is dropped off a cliff and reaches a speed of 29.4 meters per second after 3.0 s What is the balls average acceleration?

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A person on a very high cliff throws a ball vertically up at an initial speed of 13.0 ms Neglect friction whats the speed at the highest point the acceleration at the highest point?

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Suppose a rock is dropped off a cliff with an initial speed of 0 What is the rock's speed after 5 seconds in if it encounters no air resistance?

49