If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
If a ball is thrown vertically upward, the x-component of its initial velocity is zero.
Zero
If it's fired horizontally, then its initial vertical velocity is zero. After that, the vertical velocityincreases by 9.8 meters per second every second, directed downward, and the projectile hitsthe ground after roughly 3.8 seconds.Exactly the same vertical motion as if it were dropped from the gun muzzle, with no horizontal velocity.
Just before it reaches the highest point, the vertical component of velocity is upward.Just after it passes the highest point, the vertical component of velocity is downward.There's no way you can change from an upward velocity to a downward velocity smoothlywithout velocity being zero at some instant. A.True.
The horizontal component of velocity for a projectile is not affected by the vertical component at all. Horizontal component is measured as xcos(theta) Vertical component is measured as xsin(theta) Whereas theta is the angle, and x is the magnitude, or initial speed.
Because gravity is acting on the vertical component, exerting a constant -9.8m/s2 worth of acceleration.
Ignoring air resistance, the horizontal component of velocity has no connection with, and no effect on, the vertical component. Two bodies that leave the top of the building simultaneously with the same vertical velocity hit the ground at the same time, regardless of their horizontal velocities or their masses. That's the same as saying that a bullet fired horizontally from a gun and a bullet or a stone dropped from the gun's muzzle at the same instant hit the ground at the same instant. Strange but true.
If it's fired horizontally, then its initial vertical velocity is zero. After that, the vertical velocityincreases by 9.8 meters per second every second, directed downward, and the projectile hitsthe ground after roughly 3.8 seconds.Exactly the same vertical motion as if it were dropped from the gun muzzle, with no horizontal velocity.
Just before it reaches the highest point, the vertical component of velocity is upward.Just after it passes the highest point, the vertical component of velocity is downward.There's no way you can change from an upward velocity to a downward velocity smoothlywithout velocity being zero at some instant. A.True.
The horizontal component of velocity for a projectile is not affected by the vertical component at all. Horizontal component is measured as xcos(theta) Vertical component is measured as xsin(theta) Whereas theta is the angle, and x is the magnitude, or initial speed.
Ignoring air resistance, the horizontal component of velocity has no connection with, and no effect on, the vertical component. Two bodies that leave the top of the building simultaneously with the same vertical velocity hit the ground at the same time, regardless of their horizontal velocities or their masses. That's the same as saying that a bullet fired horizontally from a gun and a bullet or a stone dropped from the gun's muzzle at the same instant hit the ground at the same instant. Strange but true.
Because gravity is acting on the vertical component, exerting a constant -9.8m/s2 worth of acceleration.
No. They both hit the ground at the same time, because the VERTICAL component of velocity in both cases is the same.
No. They both hit the ground at the same time. This is because the VERTICAL component of velocity in both cases is the same.
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
The vertical velocity is zero at the highest point. It has ceased moving upward and will begin moving downward. Gravity and air resistance will have negated the original vertical velocity (y-component). So the velocity at the highest point has only a horizontal or x-component.
44
Gravity... I think
If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).