No. They both hit the ground at the same time, because the
VERTICAL component of velocity in both cases is the same.
False, provided the drop occurs no sooner than the throw, and the ground is flat .
No. They both hit the ground at the same time. This is because the VERTICAL component of velocity in both cases is the same.
yes because they have the same gravitational potential
they hit same time
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
False, provided the drop occurs no sooner than the throw, and the ground is flat .
No. They both hit the ground at the same time. This is because the VERTICAL component of velocity in both cases is the same.
yes because they have the same gravitational potential
they hit same time
They should reach the ground together, since their initial vertical speed is the same, namely zero.
If both raindrops are dropped at the same time from the same height, then no, it does not take any longer, They will hit the ground at the same time because the vertical distance to the ground remains the same.One just travels further away
4 seconds
A cannonball fired horizontally and one dropped from the height of the muzzle simultaneous with the shot will hit the ground at the same instant, provided only that the ground under the muzzle and the ground where the shot lands are at the same elevation, i.e. the shot was not fired off the edge of a cliff or into the side of a mountain. To solve this kind of problems, it often helps to separate the movement, or the speed, into vertical and horizontal components. In this case, the vertical component of the speed is the same.
You don't need any work to drop a stone!
Interesting question. But when the object is at rest the potential energy of the object is 0, on the surface that is. When it is on a height h it's potential energy increase and when it is dropped from that height all that potential energy gets converted to kinetic energy just before hitting the ground. This extra force comes from this kinetic energy.
as done in Galileo's experiment when he dropped a large rock and a feather from a tall tower both hit the ground at the same moment when dropped from the same height.
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)