False, provided the drop occurs no sooner than the throw, and the ground is flat .
No, objects fall at the same rate regardless of their horizontal velocity. Both objects would hit the ground at the same time if dropped from the same height.
The ball dropped from 4m height has more kinetic energy just before it hits the ground because it has a higher velocity due to falling from a greater height. Kinetic energy is directly proportional to both mass and the square of velocity, so the ball dropped from 4m height will have more kinetic energy than the one dropped from 2m height.
No, both objects will hit the ground at the same time if there is no air resistance acting on them. This is known as the principle of equivalence, which states that in the absence of air resistance, all objects will fall at the same rate regardless of their mass or how they are initially given velocity.
Still accelerating til it hits earth. ====================================== The height from which she dropped the ball is irrelevant. In any case, the ball was most likely moving at the greatest speed just as it hit the ground. The answer to the question is: zero.
Both arrows will hit the ground at the same time because the force of gravity acts equally on both arrows, regardless of their initial horizontal or vertical motion. The vertical component of the horizontally shot arrow's motion does not affect the time it takes to fall to the ground.
No, objects fall at the same rate regardless of their horizontal velocity. Both objects would hit the ground at the same time if dropped from the same height.
The ball dropped from 4m height has more kinetic energy just before it hits the ground because it has a higher velocity due to falling from a greater height. Kinetic energy is directly proportional to both mass and the square of velocity, so the ball dropped from 4m height will have more kinetic energy than the one dropped from 2m height.
No, both objects will hit the ground at the same time if there is no air resistance acting on them. This is known as the principle of equivalence, which states that in the absence of air resistance, all objects will fall at the same rate regardless of their mass or how they are initially given velocity.
Still accelerating til it hits earth. ====================================== The height from which she dropped the ball is irrelevant. In any case, the ball was most likely moving at the greatest speed just as it hit the ground. The answer to the question is: zero.
They should reach the ground together, since their initial vertical speed is the same, namely zero.
Both arrows will hit the ground at the same time because the force of gravity acts equally on both arrows, regardless of their initial horizontal or vertical motion. The vertical component of the horizontally shot arrow's motion does not affect the time it takes to fall to the ground.
No, both objects will hit the ground at the same time, assuming air resistance is negligible. This is because the time it takes for an object to fall is only influenced by its initial vertical velocity and the acceleration due to gravity, not its horizontal motion.
When an object is dropped from a certain height, the time it takes to reach the ground is independent of the height (assuming no air resistance). Therefore, whether you drop the object from three times the initial height or the original height, it will still take the same time (T) to reach the ground.
No, both objects will hit the ground at the same time if there is no air resistance influencing their fall. This is because in the absence of other forces, the only force acting on both objects is gravity, which causes them to accelerate at the same rate regardless of their horizontal velocity.
If both raindrops are dropped at the same time from the same height, then no, it does not take any longer, They will hit the ground at the same time because the vertical distance to the ground remains the same.One just travels further away
You don't need any work to drop a stone!
Interesting question. But when the object is at rest the potential energy of the object is 0, on the surface that is. When it is on a height h it's potential energy increase and when it is dropped from that height all that potential energy gets converted to kinetic energy just before hitting the ground. This extra force comes from this kinetic energy.