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A ball of weight 10N is dropped freely from rest at a height of 4 m.what is its total mechanical energy after it has traveled 1 meter?
Wiki User
∙ 13y ago
If you are ignoring energy lost due to friction, the total mechanical energy will be the same after it has traveled 1 meter as when it was dropped. This means the easiest way to solve the problem is to find the mechanical energy at the beginning, when the ball is at rest and all of its mechanical energy is gravitational potential energy. Gravitational potential energy equals mass*g*height. Since mass*g equals weight, we can just multiply 10N by 4m, making the total mechanical energy 40J.
After it has traveled 1 meter, some of the gravitational potential energy has been converted into kinetic energy. The gravitational potential energy is just the weight of 10N multiplied by the height of 3m, or 30J. To find the kinetic energy, we need to find velocity2, which equals 2 times acceleration (g) times displacement (1m) when the initial velocity is 0. We also need the mass, which is weight (10N) divided by g. Kinetic energy equals (1/2)*mass*velocity2, so we get (1/2)*10N÷g*2*g*1m, which equals 10J, so the total mechanical energy is still 40J.
Wiki User
∙ 13y ago
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