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What is toggle bit?
when dealing with bit, there are only 2 bits which are '0' and '1'. when the current bit is '0', if we toggle this bit, it will become '1' and when the current bit is '1', if we toggle this bit, it will become '0' that is
In a bit wise XOR operation between two operands when is the resulting bit 1?
if they differ: A B Q 0 0 0 0 1 1 1 0 1 1 1 0
What is the capacity of a bit?
A single bit can be either 0 or 1.
What is capacity of a bit?
A single bit can be either 0 or 1.
What is the Total number of 1 bit combinations are?
The total number of 1-bit combinations is 2. This is because a single bit can have two possible values: 0 or 1. Therefore, the combinations are {0, 1}.
What tiny unit of information storage consisting of an onoff signal?
Bit.
Is it true that each 1 and 0 in the binary system represents 1 bit of computer code?
Ye, 1 bit can either represent on "1" or off "0".
What is A 1 or 0 in the binary number system is called?
each 1/0 is called a bit, 8 bits = a bite
6 How many values does a binary digit bit have?
It can have 0 to 1 It can have 0 to 1
Consider even parity design a haming code for the ascii character 'A'?
The ASCII character A is a 65 in decimal. That means it is 0100 0001 in binary. The hamming code uses extra bits to encode parity information, so the character A would be: _ _ 0 _ 1 0 0 _ 0 0 0 1 where the _ indicates a parity bit * Position 1 checks bits 1,3,5,7,9,11:? _ 0_ 1 0 0 _ 0 0 01With even parity, the bit must be a 10 _ 0_ 1 0 0 _ 0 0 01* Position 2 checks bits 2,3,6,7,10,11:0 ? 0 _ 1 0 0 _ 0 0 0 1With even parity, the bit must be a 00 0 0 _ 1 0 0 _ 0 0 0 1* Position 4 checks bits 4,5,6,7,12:0 0 0 ? 1 0 0 _ 0 0 0 1With even parity, the bit must be a 0:0 0 0 0 1 0 0 _ 0 0 0 1* Position 8 checks bits 8,9,10,11,12:0 0 0 0 1 0 0 ? 0 0 0 1With even parity, the bit must be a 10 0 0 0 1 0 0 1 0 0 0 1 The encoded character is 0 0 0 0 1 0 0 1 0 0 0 1
What is the gray code for 1111?
To convert the binary number 1111 to Gray code, you keep the most significant bit (MSB) the same and then perform an XOR operation between each bit and the bit to its left. The conversion steps are as follows: the MSB is 1, the second bit is 1 XOR 1 = 0, the third bit is 1 XOR 1 = 0, and the fourth bit is 1 XOR 1 = 0. Therefore, the Gray code for 1111 is 1000.
Suppose that the UDP receiver computes the Internet checksum for the received UDP segment and finds that it matches the value carried in the checksum field Can the receiver be absolutely certain tha?
UDP receiver computes the Internet checksum for the received UDP segment and finds that it matches the value carried in the checksum field, it can still not be absolutely sure that there are no bit errors at all.Once the checksum is added to the messages, only the presence of 1-bit errors can be detected.If there are any 2-bit errors , any two bits in the message can be changed which may still result in a perfect addition to result in all 1s.Example:Sum of the three 8 byte bytesCarry 1 1 1 1 10 1 0 1 0 0 1 1+ 0 1 1 0 0 1 1 0+ 0 1 1 1 0 1 0 01 0 1 0 1 1 0 1One's complement of 10101101 = 01010010This one's compliment will be used as the check sum at the receiving end by adding it to the three 8 byte bits.The receiver will conclude that there are no 1 bit errors if by adding the checksum to the three messages, the solution contains of only 1s as shown below for the current example.Carry 1 1 1 1 10 1 0 1 0 0 1 1+ 0 1 1 0 0 1 1 0+ 0 1 1 1 0 1 0 0+ 0 1 0 1 0 0 1 01 1 1 1 1 1 1 1If there are any 0s in the above addition then, there is a 1-bit error.Consider adding the checksum addition from the above question. When, we modify 2 messages with 2-bit errors.Carry 1 1 1 1 10 1 0 1 0 0 1 1+ 0 0 0 0 0 1 1 0 ß 2 bit error+ 0 0 0 1 0 1 0 0 ß 2 bit error+ 0 1 0 1 0 0 1 01 1 1 1 1 1 1 1 ß Answer still contains only 1s
