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A block of mass 500G is pulled from rest on a horizontal frictionless bench by a steady force F and travels 8M in 2 s find the acceleration and the value of F?
Wiki User
∙ 15y ago
Verified answer
Equations:
F=m*a
d=vi*t+1/2*a*t²
Given Variables
m=.5kg
vi=0m/s
d=8m
t=2s
8=0m/s*2s+1/2*a*2s²
a=4m/s²
F=.5kg*4m/s
F=2N
Wiki User
∙ 15y ago
Anonymous
Nothabo Moyo
The acceleration can be calculated using the equation ( a = \frac{2s}{t^2} ), where s is the distance traveled and t is the time taken. Plugging in the values, we get ( a = \frac{2(8)}{2^2} = 4 , m/s^2 ). The value of force ( F ) can be calculated using Newton's second law as ( F = ma ), where ( m = 0.5 , kg ) and ( a = 4 , m/s^2 ). Thus, the force ( F = 0.5 \times 4 = 2 , N ).
Anonymous
8/2=4
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Which forces act mostly in a horizontal direction?
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Which forces act mostly in a horizontal direction?
Frictional force and tension in a horizontal rope are two common forces that act mostly in a horizontal direction. These forces are important in scenarios involving objects moving along a surface or being pulled horizontally.
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What is the acceleration of a 38 kg block of cement when pulled sideways with a net force of 245 N?
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