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If a car is moving 42 meters per second after 6 sectons, the average acceletion is 7 meters per second per second. It is an average, given two points of data, and it is not the instantaneous acceleration at any point in time.
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
I assume the object starts from rest. The speed will be 16*3 which is 48m/s
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
veliocity = = acceleration x time v = at v = 150 km /hr = 150/60 km/minute t = 3 minutes a = v/t = 150/60/3 = 5/6 km/min/min = .833 km/min/min
It is accelerating at 1.2m/s per second.
The average acceleration is given by the expression a ∆v/∆t (15 m/s)/5s 3m/s2 where a is acceleration, v is velocity, and t is time. ∆ (final-initial) value.
If a car is moving 42 meters per second after 6 sectons, the average acceletion is 7 meters per second per second. It is an average, given two points of data, and it is not the instantaneous acceleration at any point in time.
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
What do you mean "show your work" ? ! ?Did this question come from a homework assignment or something ?That's not an acceptable use of this website.Coach White's acceleration is 28.89 meters per second2, which is almost 3 G's.
2.0 m/s^2
the acceleration is increasing speed Acceleration = velocity change / time velocity change = 0 to 25 mm/hr = 25 mm/hr time = 5 seconds therefore acceleration = 25/5 mm/hr per second = 5 mm per hour per second.
distance = 1/2 acceleration x time squared; acceleration is 7 m/s/s
I assume the object starts from rest. The speed will be 16*3 which is 48m/s
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
vf=54 km/hr vi=0km/hr t=5sec/0.001hr a=5400 km/hr 54km/hr- 0km/hr --------------------- 0.001 hr
Average speed = (250 / 5) = 50 meters per second.Initial speed = 0Final speed = 100 m/sAcceleration = (100 / 5) = 20 m/s2===> Must be a rocket-propelled ball; its acceleration is 2G !