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A car traveling along a level road at speed v slams on the brakes and skids to a stop If the force of friction on the car is half the car's weight how far does the car slide?
Wiki User
∙ 13y ago
The kinetic energy of the moving car is ½ m v2
The weight is m g.
Work is F d
Where m is mass in kg
v is velocity in m/s
g is acceleration due to gravity, 9.8 m/s2
F is force in Newtons
d is distance in meters/metres
Since the force of friction is half the weight, F = 0.5 m g.
Work done by friction must equal out the initial kinetic energy of the car. Work done by the force of friction is Force x Distance, so the distance is Work / Force.
d = (½ m v2) / ½ m g
d = (½ v2) / ½ g
d = v2 / g
d = v2/9.8 meters
Wiki User
∙ 13y ago
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