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Apply to the equation V=U+at . The answer is 40.
Given: V0 = 24 m/s, a = 2 m/s2, t = 8 s. (a = acceleration, t = time) Vf = V0 + a t Vf = (24) + (2) (8) = 24 + 16 = 40 m/s.
Given: V0 = 24 m/s, a = 2 m/s2, t = 8 s. (a = acceleration, t = time) Vf = V0 + a t Vf = (24) + (2) (8) = 24 + 16 = 40 m/s.
velocity is found by dividing the distance with time. In a second the height traveled is found by multiplying the velocity by the time taken and then dividing the answer by two.
No. An object traveling at a constant velocity is not accelerating.
Apply to the equation V=U+at . The answer is 40.
what velocity is a taint by an object that is accelerated at .3om/s for the distance of 54m if its initial velocity is 50m/s
Vf = Vi + a t
It means that acceleration is constant. This meaning that velocity is varying with respect to time, we see this by this formula (v - v(initial) ) / t (Time).
uniformly accelerated motion
Uniformly accelerated
Given: V0 = 24 m/s, a = 2 m/s2, t = 8 s. (a = acceleration, t = time) Vf = V0 + a t Vf = (24) + (2) (8) = 24 + 16 = 40 m/s.
Given: V0 = 24 m/s, a = 2 m/s2, t = 8 s. (a = acceleration, t = time) Vf = V0 + a t Vf = (24) + (2) (8) = 24 + 16 = 40 m/s.
velocity is found by dividing the distance with time. In a second the height traveled is found by multiplying the velocity by the time taken and then dividing the answer by two.
2.1
An object can only accelerate if its velocity changes.
No. An object traveling at a constant velocity is not accelerating.