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A cat is chasing a mouse on the top of a table 1.75 m above the floor if the cat slides off the edge of the table at a velocity of 8 ms a how long does it take to hit the floor?
Wiki User
∙ 15y ago
4.5 seconds thats one awnser but is the cat a sumo cuz then the table would break and he would fall faster
Wiki User
∙ 15y ago
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What is maintained at a constant height of 10 m in a tankcalculate the velocity of efflux?
In order to calculate that, we'd also need to knowthe substance in the tankthe size and shape of the outletthe height of the outlet above the floor of the tank.
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For comparison what is the magnitude of the acceleration a test tube would experience if dropped from a height of 1.0 m and stopped in a 1.0-ms-long encounter with a hard floor?
Its velocity just before it hits the floor is found from kinematic equations and acceleration due to gravity; V = SqRt{2gy) = SqRt{19.6} = 4.4 m/s . The velocity after 1 ms is zero. The average deacceleration is the velocity difference divided by the time during impact; a = (4.4 - 0 )/.001 = 4400 m/ss .
If i throw a ball downward from a window at a speed of 2.5 ms How fast will it be moving when it hits the sidewalk 3.0 m below?
This would be the simple answer, ignoring air resistance, wind, and other such incooperative forces. First working out the vertical component of velocity when it hits the floor: final velocity (v) = ? Initial velocity (u) = 0 Displacement (s) = 3 Accelleration (a) = g; taken to be 9.81 Using the equationof linear motion v2 = u2 + 2as v2 = 0 + (2 * 9.81 * 3) v2 = 58.86 v = 7.672 Now we know that the horizontal component of velocity will be 2.5 ms-1 (ignoring air resistance) so now we have to find out the velocity of the ball when it hits the floor, if it is travelling at a velocity with a downwards vertical component of 7.672ms-1 and a horizontal component of 2.5ms-1 2.52 + 7.6722 = 65.1095 Square rooting that... Velocity = 8.069ms-1
How fast will a puck slide off a table if the table is 5 ft tall and the puck slides at 2ms?
Neglecting friction, if a puck is sliding at 2 m/s it will still be sliding at 2 m/s when it slides off the table. Immediately before hitting the floor, its velocity in the x-direction will still be 2 m/s but it will have accelerated to a y-velocity of approximately 6.4 m/s, yielding a total speed of 6.6 m/s.
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If a ball rolls off the edge of a table two meters above the floor and with an initial velocity of 20 meters per second what is the ball's acceleration and velocity just before it hits the ground?
The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
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A truck moving at constant velocity inside the storage compartment a rock is dropped from the midpoint of the ceiling and strikes the floor below the rock hits the floor Read more:
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