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A chemist wants to make a 10 solution of fertilizer. how much water and how much of a 30 solution should the chemist mix to get 30 L of a 10 solution?

30 liters of a 10 % solution of fertilizer has .1(30) = 3 liters of fertilizer 1 liter of 30% solution has .3 liter of fertilizer 10 liters of 30% solution has 3 liters of fertilizer so, the chemist needs 10 liters of the 30% solution and 20 liters of water to make 30 liters of a 10% solution.


What is the concentration of a solution of 10. moles of copper II nitrate in 5.0 liters of solution?

The concentration of the solution is 2.0 moles per liter. This is calculated by dividing the moles of solute (10. moles) by the volume of the solution in liters (5.0 liters).


What is the concentration of a solution of 10 moles of copper nitrate in 5.0 liters of solution?

The concentration is 2 M.


A chemist is making 200 L of a solution that is 62 percent acid He is mixing an 80 percent acid solution with a 30 percent acid solution How much of the 80 percent acid solution will he use?

The chemist will use 100 liters of the 80% acid solution and 100 liters of the 30% acid solution to make a 200-liter solution that is 62% acid. The amount of acid in the 80% solution will be 0.8 * 100 = 80 liters, and in the 30% solution, it will be 0.3 * 100 = 30 liters.


A chemist needs 4 liters of a 50 percent salt solution All she has available is a 20 percent salt solution and a 70 percent salt solution How much of each of the two solutions should she mix to obtain?

You will need more data about all densities (in kg/Litre)and you must be sure of using mass% = (g solute)/(100 g solution)Solve two equations for both X and Y:4*d50*50 = X*d20*20 + Y*d70*70 (based on salt mass balance in diff. sol'n.)4*d50 = X*d20 + Y*d70 (based on solutions mass balance)In which:dm = density of the 'm'% salt solution in kg/Litre)X and Y = volume of the 20% and 70% salt solutions respectively


A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated How much of the first 60 percent solution is needed to make a 100 L solution that is 50?

To create a 50% chlorinated solution from the 60% and 40% solutions, the chemist will need to mix the two in equal amounts. Therefore, 50 L of the 60% solution and 50 L of the 40% solution are needed to make a 100 L solution that is 50% chlorinated.


What is the molarity of a solution is defined as?

The concentration in moles of a substance in the solution


How do you find the concenration of a solution?

Concentration of a solution is recorded in molarity (M). Molarity is the moles of solute divided my liters of solution. So to find the concentration of a solution, calculate the number of moles of the solute (the chemical being dissolved) and measure the number of liters of the solution (the water), then divide them.


How do you convert concentration to molarity?

To convert concentration to molarity, you need to divide the number of moles of solute by the volume of solution in liters. This will give you the molarity of the solution.


What is the concentration of 10. moles of copper (II) nitrate in 5.0 liters of solution?

The concentration is 2 mol/L.


What solution with a low concentration of solute?

A dilute solution.


What is the ratio of moles of absolute to liters of solution called?

You think probable to molar concentration.