50
50 Liters of the 60% solution.
50liters
10
In order to reduce the percentage of acid from 80% to 50%, you would need to add another 36 kg of diluent (e.g. water).
210Type your answer here...
50 Liters of the 60% solution.
50liters
50 liters
144liters
256 liters
128 liters
6 litres of 50% + 4 litres of 25%
2m-m=m more grams he needs
some liquid volumes are not additive, leading to potentially confusing final solution volumes.
.80x+.30y=400*.62 .80x+.30y=248 This is equation one. x+y=400 x=400-y This is the second equation. .80(400-y)+.30y=248 320-.80y+.30y=248 -.50y=-72 Y=144 X=256 CHECK .80(256)+.30(144)=400(.62) 204.8+43.2=248 248=248
100ppb
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).