1st writer: You have Ohms law written wrong, here is an easy formula to use to get the right answer: V/IxR but the answer is .2 Amps (note the right answer)
2nd writer: You both have it written wrong. Ohm's Law is V=IxR. This can be used to solve Voltage, Current and Resistance with two givens. Then, when Power is presented through Watt's Law (P=IxV), you are able to solve for any of the four also with two givens. http://www.aob.com.au/resources.html Here's OUR set-up: I=V/R
This is the substitution: I=12V/60Ω Answer=0.2A OR 200mA
There is no question. Please restate the question.
200 ma. or .2 Amps
E=IR
Where:
E = EMF in volts
I = Current in Amps
R = resistance in Ohms
by ohms law .
V=IR
&
I=V / R
I = 60 / 12
I = 5 Amp
This is the actual current which is flowing thrugh the circuit .
5a
Backward diode
This is probably the I-V characteristic: Apply a voltage to one terminal of the component, the current through the component is then recorded; this is done for varying values, and is plotted out on a graph. For transistors, this shows where the "linear operation" region is; for diodes, this shows the "turn on" voltage. Such characteristics will be in the data sheets for whatever component you're using.
An apparatus that assesses a complex mixture of wave forms by separating out their component frequencies and displaying their distribution.
No, it isn't. That's why we use it to clean electrical equipements ( dry ice blasting). it can be added that is how circuit boards are tested for low temperature operation
A photo resistor decreases in resistance as illumination increases. I don't believe there are any discrete components that accomplish what you are asking. You may need to use a photo resistor, combined with a transistor to invert this operation.
A diode is an electronic component which only allows the current to pass through it in one direction. This is useful in many aplications, such as preventing current to flow in the wrong direction in a circuit. A resistor is also an electronic component, but instead of preventing the current from moving in a certain direction the resistor creates an electrical resistance which will effect the current passing through it. The larger the resistance of the resistor, which is measured in Ohm, the greater the effect it will have on the current.
Usually a volt meter is placed across a component to measure the voltage drop across that component. Doing this places the volt meter resistance in parallel with that component's resistance, which will always lower the total resistance. Since the volt meter resistance is usually very large relative to the resistance of the element being measured, the total resistance does not change significantly. The formula for total resistance of two parallel elements is: Rtot = (R1*R2)/(R1+R2), as R1 (the volt meter) >> R2, Rtot ~= (R1*R2) / (R1) = R2 If a volt meter is placed into a circuit instead of around an element of that circuit, it will raise the resistance of the circuit, load the circuit with, and interrupt "normal" operation of the circuit (normal operation = how things would be without the meter in place). More importantly, the volt meter would then be measuring the voltage developped across itself (instead of an element of the circuit), which is not the point of this tool / this would be a misapplication of a volt meter.
the resistance needs a leader because its a serious operation
Component ware is one of the kind of the application software in which the each of program does a specific operation.
operation of separating the component parts
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ALU
Backward diode
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Instruction Decoder
Electrical energy.
A component is a piece of the system, and is vital to the operation of the system or another component thereof. For example, a driver is a component that allows the system software to interface with hardware, and is the only way that a user application can interact with that hardware. A system utility is not vital to the system's operation, but can help diagnose problems and keep the system running smoothly.