A few comments first of all. Current flows 'through', not 'across'. There is no such thing as 'electrical power'; power is power -period! The symbol for volts is 'V', not 'v'.
To answer your question, you can find the power of the lamp using the equation: P = U I
where:
P = power in watts
U = potential difference in volts
I = current in amperes
Changing the potential difference in a circuit does not change the resistance. Rather, it changes the current.
Voltage = Current x Resistance giving us Current = Voltage / Resistance i.e. Voltage divided by resistance
think of potential as pressure and current as flow. you can have pressure in a water hose with out flow. open the valve and current happens. The difference in potential divided by the impedance is equal the current.
current flows as a result of potential difference i.e. in a circuit if there is no voltage difference between two points, no current can flow between those two points. So voltage has to be produced first.
Higher input current means higher voltage. A bulb contains one filament (tungsten) when input power supply passing through this filament, the filament gets hot and makes a red color and then yellow. This filament needs only electrons flow, but if we are operating higher current bulb efficiency will down, when the filament burns out.
When the flashlight is ON , electrical current is flowing from one terminal of thebattery, through the light-bulb filament, to the other terminal of the battery.
The current supplied to the filament for heating is defined as the Filament current. whereas When the filament is heated to a high temperature, the electrons are emitted. The flow of electrons form Cathode to anode is the tube Current.
The name for the potential difference that causes current to flow is voltage.
The current supplied to the filament of an electron tube for heating.
No.
The function of the bulb in a flashlight is to generate some light when some electrical current passes through it. Note: That's actually the whole purpose of the flashlight. If there were no part of it that generated any light, then you do just as well without the flashlight altogether.
Current is proportional to the potential difference and inversely proportional to resistance. Ohm's law: Current equals voltage divided by resistance
A lamp with a thick filament will draw more current. What restricts the current flow in the filament is the resistance of the filament which increases as the temperature of the filament increases. A thin filament requires less energy to get heated up that a thick one so less current to achieve threshold resistance. Also a thick filament provides a broader path for current so there is less resistance per increase in degree centigrade. For these two (closely related but distinct) reasons it will require more current for the filament to get heated up to threshold resistance.
Conventional current is the flow of positive charge from higher potential to lower potential, while electric current is the flow of electrons from lower potential to higher potential.
The four forms of energy used for a flashlight are chemical energy stored in batteries, electrical energy generated by the batteries, light energy produced by the flashlight bulb or LED, and thermal energy generated as a byproduct of the light production.
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Voltage across two terminals mean there exists a potential difference, and when the circuit gets closed, due to this potential difference the current flow.